I have the following range of information available:
0% through 10% = 0.0% standard rate
11% through 14% = 2.0% standard rate
15% through 18% = 2.5% standard rate
19%+ = 3.0% standard rate
If an acocunt is designated as type "N", then the rate applied is whatever the standard rate is plus 1%.
If an account is designated as type "D1", then the rate applied is whatever the standard rate is multiplied by .75
If an account is designated as type "D2", then the rate applied is whatever the standard rate is multiplied by .5
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I have set up sheet1 as follows:
Column A, Row 1 = 0 (beginning of range)
Column B, Row 1 = .1 (end of range)
Column C, Row 1 = 0 (standard rate applied)
Column A, Row 2 = .11 (begin of range)
Column B, Row 2 = .14 (end of range)
Column C, Row 2 = .02 (standard rate)
Column A, Row 3 = .15 (begin of range)
Column B, Row 3 = .18 (end of range)
Column C, Row 3 = .025 (standard rate)
Column A, Row 4 = .19 (begin of range)
Column B, Row 4 = 1.00 (end of range)
Column C, Row 4 = .03 (standard rate)
Column E, Row 1 = D2
Column E, Row 2 = .18225 (an example of a value within a range)
Column E, Row 3 = (If, then statement)
My hope is that when the if-then statement is implemented, the result using the example given would be .0125 (.025 standard rate multiplied by .5). If I change Column E, Row 1 to 'N', then I would expect the result to be .035 (.025 standard rate plus .01). If I then change Column E, Row 2 to .21285, I would expect the result to be .04 (.03 standard rate plus .01).
Can anyone help me solve this?
Thanks,
MidCon
Welcome to the forum, MidCon.
Please take a few minutes to read the forum rules about thread titles, and then amend yours accordingly.
Microsoft MVP - Excel
Entia non sunt multiplicanda sine necessitate
I ammended the title by starting a new topic. I could not change the title of my topic so I went that route. You can lock this topic if need be. I'm unsure if my new title is acceptable. If you could look at it to see if it is now descriptive enough that would be appreciated.
Thanks,
MidCon
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