Thread: This formula is too advanced for me.

This formula is too advanced for me.

The number series that will appear in Cell A1 are listed below:

4.0 thru 4.999999999, 5.0 thru 5.999999999, 6.0 thru 6.999999999, 7.0 thru 7.999999999, 8.0 thru 8.999999999, 9.0 thru 9.999999999, 10.0 thru 10.999999999, 11.0 thru 11.999999999, 12.0 thru 12.999999999.

I am trying to develop a formula for Cell B1 that will resolve the problem:

Each one of these nine series of numbers above, will have its own multiplier.
Note: The multiplier value will be assigned simply by adjusting the formula.

Example:
4.0 thru 4.999999999 X $5.00, 5.0 thru 5.999999999 X $13.00, 6.0 thru 6.999999999 X $15.00, – Etc. up to: 12.0 thru 12.999999999 X $25.00

Any help would be greatly appreciated.
Thanks

Its not clear to me what the "etc." should be, but you can fill that into this formula.

=LOOKUP(A1,{4,5,6,7,8,9,10,11,12,13},{5, 13, 15, "7 value", "8 value", "9 value", "10 value", "11 value", 25})

Hi okenter,

This sounds like a job for the Choose() function.
In cell B1 put this formula

=CHOOSE(FLOOR(A1,1) -3,5,13,15,22,35,42,47,72,76) *A1

Change the 5,13,15... to the multipliers you desire.
Then read http://www.excelfunctions.net/ExcelChoose.html to see why it works.

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