normalizing data -- a twist

[Brad]

I have the following data in the left-most column and the results of a
formula in the next:

0.006149 0.710222
0.004668 0.676867
-0.00354 0.49206
-0.01529 0.227635
-0.01644 0.201561
-0.0195 0.132744
-0.01835 0.15867
-0.0254 0
-0.02151 0.087515
-0.01532 0.226867
-0.00885 0.372547
0 0.571774
0.011987 0.841663
0.016434 0.941773
0.01902 1


The formula normalizes the first column data so that the values in the
second column are valued between 1 and 0. The formula is:

=(A131-SMALL($A$131:$A$145,1))/(LARGE($A$131:$A$145,1)-SMALL($A$131:$A$145,1))

My problem is that, in the event that there is a zero value in the column of
numbers (the numbers almost always include positive and negative values), I
would like the normalizing formula to show a zero value in the results
there. Note that the actual 0 datum when normalized through this range,
equals .571774.

Since the zero value would normally not be the middle value of the range of
numbers, I think if I could come up with a formula to normalize all the
values greater than 0 with a range of 0 to 1, then all negative numbers 0
to -1, and 0= 0, I'd have what I am looking for. I'd appreciate any thoughts
here and my thanks in advance. Brad

[Bill Kuunders]

Not 100 % sure whether this is what you're looking for but it might get you
on the way.
Normalising the pos numbers by dividing them by the pos range and the neg's
by the neg range
otherwise return zero.
=IF(A131>0,A131/LARGE($A$131:$A$145,1),IF(A131<0,-A131/SMALL($A$131:$A$145,1),0))

Greetings from New Zealand
Bill K

"Brad" <[email protected]> wrote in message
news:[email protected]...
>I have the following data in the left-most column and the results of a
>formula in the next:
>
> 0.006149 0.710222
> 0.004668 0.676867
> -0.00354 0.49206
> -0.01529 0.227635
> -0.01644 0.201561
> -0.0195 0.132744
> -0.01835 0.15867
> -0.0254 0
> -0.02151 0.087515
> -0.01532 0.226867
> -0.00885 0.372547
> 0 0.571774
> 0.011987 0.841663
> 0.016434 0.941773
> 0.01902 1
>
>
> The formula normalizes the first column data so that the values in the
> second column are valued between 1 and 0. The formula is:
>
> =(A131-SMALL($A$131:$A$145,1))/(LARGE($A$131:$A$145,1)-SMALL($A$131:$A$145,1))
>
> My problem is that, in the event that there is a zero value in the column
> of numbers (the numbers almost always include positive and negative
> values), I would like the normalizing formula to show a zero value in the
> results there. Note that the actual 0 datum when normalized through this
> range, equals .571774.
>
> Since the zero value would normally not be the middle value of the range
> of numbers, I think if I could come up with a formula to normalize all the
> values greater than 0 with a range of 0 to 1, then all negative numbers 0
> to -1, and 0= 0, I'd have what I am looking for. I'd appreciate any
> thoughts here and my thanks in advance. Brad
>
>

[mangesh_yadav]

Another method:
Find the absolute value of you column A, and use your formula on this second column.

Col B = ABS(A131)
Col C =
=IF(B131>0,B131/LARGE($B$131:$B$145,1),IF(B131<0,-B131/SMALL($B$131:$B$145,1),0))


Mangesh

[Bill Kuunders]

Mangesh
I wonder........
How can B131 be smaller than 0 if it is the absolute of A131?

--
Greetings from New Zealand
Bill K

"mangesh_yadav" <[email protected]>
wrote in message
news:[email protected]...
>
> Another method:
> Find the absolute value of you column A, and use your formula on this
> second column.
>
> Col B = ABS(A131)
> Col C =
> =IF(B131>0,B131/LARGE($B$131:$B$145,1),IF(B131<0,-B131/SMALL($B$131:$B$145,1),0))
>
>
> Mangesh
>
>
> --
> mangesh_yadav
> ------------------------------------------------------------------------
> mangesh_yadav's Profile:
> http://www.excelforum.com/member.php...o&userid=10470
> View this thread: http://www.excelforum.com/showthread...hreadid=375313
>

[Mangesh Yadav]

Hi Bill,

You are right. I didn't take a second look at the formula. Just saw that
using the ABS() will solve the problem of the OP.

Mangesh



"Bill Kuunders" <[email protected]> wrote in message
news:[email protected]...
> Mangesh
> I wonder........
> How can B131 be smaller than 0 if it is the absolute of A131?
>
> --
> Greetings from New Zealand
> Bill K
>
> "mangesh_yadav"
<[email protected]>
> wrote in message
> news:[email protected]...
> >
> > Another method:
> > Find the absolute value of you column A, and use your formula on this
> > second column.
> >
> > Col B = ABS(A131)
> > Col C =
> >
=IF(B131>0,B131/LARGE($B$131:$B$145,1),IF(B131<0,-B131/SMALL($B$131:$B$145,1
),0))
> >
> >
> > Mangesh
> >
> >
> > --
> > mangesh_yadav
> > ------------------------------------------------------------------------
> > mangesh_yadav's Profile:
> > http://www.excelforum.com/member.php...o&userid=10470
> > View this thread:
http://www.excelforum.com/showthread...hreadid=375313
> >
>
>

[Harlan Grove]

Brad wrote...
>I have the following data in the left-most column and the results of a
>formula in the next:
....
>The formula normalizes the first column data so that the values in the
>second column are valued between 1 and 0. The formula is:
>
>=(A131-SMALL($A$131:$A$145,1))/(LARGE($A$131:$A$145,1)-SMALL($A$131:$A$145,1))
>
>My problem is that, in the event that there is a zero value in the column of
>numbers (the numbers almost always include positive and negative values), I
>would like the normalizing formula to show a zero value in the results
>there. Note that the actual 0 datum when normalized through this range,
>equals .571774.

What are you trying to accomplish by this? If your data values span
positive and negative values, then they must also span zero values
unless the underlying process is discontinuous at zero, but in that
case you should never get a zero data value.

>Since the zero value would normally not be the middle value of the range of
>numbers, I think if I could come up with a formula to normalize all the
>values greater than 0 with a range of 0 to 1, then all negative numbers 0
>to -1, and 0= 0, I'd have what I am looking for. . . .

I'd guess this means that you're unconcerned about the relative
absolute values of the averages of positive and negative values, e.g.,
if positive values spanned 0.05 to 1.8 while negative values spanned
-0.001 to -0.080, you'd be unconcerned that normalized 1.0 corresponded
to original 1.8 while normalized -1.0 corresponded to -0.080. If so,
try the array formula

=A131/MAX(IF(SIGN($A$131:$A$145)=SIGN(A131),ABS($A$131:$A$145)),--(A131=0))

[Tushar Mehta]

Dunno if you are still looking for a solution...

Based on your current results, the algorithm you are using is (X-Xmin)/
(Xmax-Xmin), which is what I would have expected.

In article <[email protected]>, [email protected]
says...
>
> Since the zero value would normally not be the middle value of the range of
> numbers, I think if I could come up with a formula to normalize all the
> values greater than 0 with a range of 0 to 1, then all negative numbers 0
> to -1, and 0= 0, I'd have what I am looking for. I'd appreciate any thoughts
> here and my thanks in advance. Brad

You need to clarify what you want to do. When you write that the
positive numbers should be in the range 0 to 1, does that mean you want
to lowest number to be 0? If so, subsequent to the normalization, you
could land up with multiple zeros. How will you distinguish between
them? In any case, if that's what you want...

Suppose your data are in B3:B17. Define a bunch of names (Insert |
Name > Define...)

Vals =Sheet1!$B$3:$B$17
NegVals =IF(Vals<0,Vals)
PosVals =IF(Vals>0,Vals)
NegValsMax =MAX(NegVals)
NegValsMin =MIN(NegVals)
PosValsMax =MAX(PosVals)
PosValsMin =MIN(PosVals)


Now, enter, say in G3, the formula
=IF(B3<0,-(B3-NegValsMin)/(NegValsMax-NegValsMin),IF(B3>0,(B3-
PosValsMin)/(PosValsMax-PosValsMin),0))

Copy G3 as far down G as necessary.

You will now have one set of values going from -1 to 0, one going from
0 to 1 and one consisting of 0.

--
Regards,

Tushar Mehta
www.tushar-mehta.com
Excel, PowerPoint, and VBA add-ins, tutorials
Custom MS Office productivity solutions

In article <[email protected]>, [email protected]
says...
> I have the following data in the left-most column and the results of a
> formula in the next:
>
> 0.006149 0.710222
> 0.004668 0.676867
> -0.00354 0.49206
> -0.01529 0.227635
> -0.01644 0.201561
> -0.0195 0.132744
> -0.01835 0.15867
> -0.0254 0
> -0.02151 0.087515
> -0.01532 0.226867
> -0.00885 0.372547
> 0 0.571774
> 0.011987 0.841663
> 0.016434 0.941773
> 0.01902 1
>
>
> The formula normalizes the first column data so that the values in the
> second column are valued between 1 and 0. The formula is:
>
> =(A131-SMALL($A$131:$A$145,1))/(LARGE($A$131:$A$145,1)-SMALL($A$131:$A$145,1))
>
> My problem is that, in the event that there is a zero value in the column of
> numbers (the numbers almost always include positive and negative values), I
> would like the normalizing formula to show a zero value in the results
> there. Note that the actual 0 datum when normalized through this range,
> equals .571774.
>
> Since the zero value would normally not be the middle value of the range of
> numbers, I think if I could come up with a formula to normalize all the
> values greater than 0 with a range of 0 to 1, then all negative numbers 0
> to -1, and 0= 0, I'd have what I am looking for. I'd appreciate any thoughts
> here and my thanks in advance. Brad
>
>
>