Transposing Formulas

[Johno]

Can anyone help me to transpose this decibel formula, DECIBEL = V1/V2 LOG20, If I know V1 and I know the decibel I need to work out V2 .... Thanks

[JE McGimpsey]

A little algebra:

V2 = V1/Decibel Log20

In article <[email protected]>,
Johno <[email protected]> wrote:

> Can anyone help me to transpose this decibel formula, DECIBEL = V1/V2
> LOG20, If I know V1 and I know the decibel I need to work out V2 ....
> Thanks

[Johno]

A little algebra:

V2 = V1/Decibel Log20

In article <[email protected]>,
Johno <[email protected]> wrote:

> Can anyone help me to transpose this decibel formula, DECIBEL = V1/V2
> LOG20, If I know V1 and I know the decibel I need to work out V2 ....
> Thanks

Thanks but I'm not so sure this works out exactly, if I use 1OO as V1 and 50 as V2 then the decibel figure is 6.02 .... if I then work back using the formula V2 = V1/Decibel Log 20 instead of V2 equalling 50 as in the first formula it equals 6.41 not 6.02 and if other figures are substituted and then worked back the error varies .... can anyone shed some light. ... Regards

[JE McGimpsey]

Well, it helps to start out with the right formula. Instead of

DECIBEL = V1/V2 LOG 20

the formula is actually

DECIBEL = 20 * LOG(V1/V2)

So, just rearranging and taking the antilog

V2 = V1/10^(DECIBEL/20)



In article <[email protected]>,
Johno <[email protected]> wrote:

> Thanks but I'm not so sure this works out exactly, if I use 1OO as V1
> and 50 as V2 then the decibel figure is 6.02 .... if I then work back
> using the formula V2 = V1/Decibel Log 20 instead of V2 equalling 50 as
> in the first formula it equals 6.41 not 6.02 and if other figures are
> substituted and then worked back the error varies .... can anyone shed
> some light. ... Regards