I have a text string (a directory path actually) that has several "/"
characters in it.
I'd like to find the location of the right-most occurrance of an "/".
For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
the position number of the "/" right before 'dog'?
Thanks for any help you can provide!
Here's one way:
With your text in Cell A1
B1: =LEN(A1)+1-MATCH("/",MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&(LEN(A1)))),1),0)
Note: Commit that array formula by holding down the [Ctrl][Shift] keys and
press [Enter].
Here's another way:
B1:
=LEN(LEFT(A1,SEARCH("^^",SUBSTITUTE(A1,"/","^^",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-1))+1
Just press [Enter] for that one.
Does that help?
***********
Regards,
Ron
XL2002, WinXP-Pro
"KingGeezer" wrote:
> I have a text string (a directory path actually) that has several "/"
> characters in it.
> I'd like to find the location of the right-most occurrance of an "/".
> For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
> the position number of the "/" right before 'dog'?
> Thanks for any help you can provide!
Ron! replace that bronze status with a gold one!
I think this will work just fine! It'll take me longer to *analyze* how
this work, than it did for you to answer it!
many thanks!
"Ron Coderre" wrote:
> Here's one way:
>
> With your text in Cell A1
> B1: =LEN(A1)+1-MATCH("/",MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&(LEN(A1)))),1),0)
> Note: Commit that array formula by holding down the [Ctrl][Shift] keys and
> press [Enter].
>
> Here's another way:
> B1:
> =LEN(LEFT(A1,SEARCH("^^",SUBSTITUTE(A1,"/","^^",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-1))+1
>
> Just press [Enter] for that one.
>
> Does that help?
>
> ***********
> Regards,
> Ron
>
> XL2002, WinXP-Pro
>
>
> "KingGeezer" wrote:
>
> > I have a text string (a directory path actually) that has several "/"
> > characters in it.
> > I'd like to find the location of the right-most occurrance of an "/".
> > For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
> > the position number of the "/" right before 'dog'?
> > Thanks for any help you can provide!
...A variation on Ron's first suggestion
=MATCH(2,1/(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)="/"))
confirmed with CTRL+SHIFT+ENTER
One follow-up Ron, if you're still monitoring .....
Wouldn't it be enough to stop after the 'search' function?
I get the same #, if I don't bother with the "len(left ....) parts.
Thanks; you're a star.
"KingGeezer" wrote:
> Ron! replace that bronze status with a gold one!
> I think this will work just fine! It'll take me longer to *analyze* how
> this work, than it did for you to answer it!
> many thanks!
>
> "Ron Coderre" wrote:
>
> > Here's one way:
> >
> > With your text in Cell A1
> > B1: =LEN(A1)+1-MATCH("/",MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&(LEN(A1)))),1),0)
> > Note: Commit that array formula by holding down the [Ctrl][Shift] keys and
> > press [Enter].
> >
> > Here's another way:
> > B1:
> > =LEN(LEFT(A1,SEARCH("^^",SUBSTITUTE(A1,"/","^^",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-1))+1
> >
> > Just press [Enter] for that one.
> >
> > Does that help?
> >
> > ***********
> > Regards,
> > Ron
> >
> > XL2002, WinXP-Pro
> >
> >
> > "KingGeezer" wrote:
> >
> > > I have a text string (a directory path actually) that has several "/"
> > > characters in it.
> > > I'd like to find the location of the right-most occurrance of an "/".
> > > For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
> > > the position number of the "/" right before 'dog'?
> > > Thanks for any help you can provide!
On Mon, 23 Jan 2006 15:20:02 -0800, "KingGeezer"
<[email protected]> wrote:
>I have a text string (a directory path actually) that has several "/"
>characters in it.
>I'd like to find the location of the right-most occurrance of an "/".
>For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
>the position number of the "/" right before 'dog'?
>Thanks for any help you can provide!
You can use regular expressions to easily extract whatever phrase you wish from
the string.
They are available either via VBA, or, most easily, from Longre's free
morefunc.xll add-in at http://xcell05.free.fr
For example, to get the position of the last "/"
=REGEX.FIND(A1,"\/",-1)
or
=REGEX.FIND(A1,"\/\w+$")
But, perhaps you want the last word (dog):
=REGEX.MID(A1,"\w+$")
or perhaps everything except the last word:
mama/poppa/bogus/
=REGEX.MID(A1,".*\/")
Maybe without the trailing "/"
mama/poppa/bogus
=REGEX.MID(A1,".*(?=\/)")
--ron
You're absolutely correct.
No point in making Excel work any harder than it needs to.
***********
Regards,
Ron
XL2002, WinXP-Pro
"KingGeezer" wrote:
> One follow-up Ron, if you're still monitoring .....
> Wouldn't it be enough to stop after the 'search' function?
> I get the same #, if I don't bother with the "len(left ....) parts.
> Thanks; you're a star.
>
> "KingGeezer" wrote:
>
> > Ron! replace that bronze status with a gold one!
> > I think this will work just fine! It'll take me longer to *analyze* how
> > this work, than it did for you to answer it!
> > many thanks!
> >
> > "Ron Coderre" wrote:
> >
> > > Here's one way:
> > >
> > > With your text in Cell A1
> > > B1: =LEN(A1)+1-MATCH("/",MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&(LEN(A1)))),1),0)
> > > Note: Commit that array formula by holding down the [Ctrl][Shift] keys and
> > > press [Enter].
> > >
> > > Here's another way:
> > > B1:
> > > =LEN(LEFT(A1,SEARCH("^^",SUBSTITUTE(A1,"/","^^",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-1))+1
> > >
> > > Just press [Enter] for that one.
> > >
> > > Does that help?
> > >
> > > ***********
> > > Regards,
> > > Ron
> > >
> > > XL2002, WinXP-Pro
> > >
> > >
> > > "KingGeezer" wrote:
> > >
> > > > I have a text string (a directory path actually) that has several "/"
> > > > characters in it.
> > > > I'd like to find the location of the right-most occurrance of an "/".
> > > > For example, if the string was: "mama/poppa/bogus/dog" .... how do I find
> > > > the position number of the "/" right before 'dog'?
> > > > Thanks for any help you can provide!
Ron Coderre wrote...
....
>With your text in Cell A1
>B1: =LEN(A1)+1-MATCH("/",MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&(LEN(A1)))),1),0)
>Note: Commit that array formula by holding down the [Ctrl][Shift] keys and
>press [Enter].
....
If you're going to use an array of sequential integers, you could use a
shorter, nonarray formula.
=LOOKUP(32768,FIND("/",A1,ROW(INDIRECT("1:"&LEN(A1)))))+1
and you could avoid the volatile INDIRECT using
=LOOKUP(LEN(A1),FIND("/",A1,
ROW(INDEX($1:$65536,1,1):INDEX($1:$65536,LEN(A1),1))))+1
The other approach, substituting only the final occurrence of the
substring, may be the best way to go, but it's safer to use a control
character (decimal codes 1-31 and 127) than strings of graphic
characters (all other decimal codes except 0). FWLIW, Windows .CMD
batch files use ^ as a metacharacter, so ^^ represents literal
circumflexes, so using "^^" as the substitution substring would be a
bad idea when parsing .CMD files.
Harlan, could you possibly explain the significance of the 32768?Originally Posted by Harlan Grove
BTW I don't believe you need the +1 at the end
daddylonglegs wrote...
>Harlan Grove Wrote:
>>
>> =LOOKUP(32768,FIND("/",A1,ROW(INDIRECT("1:"&LEN(A1)))))+1
>
>Harlan, could you possibly explain the significance of the 32768?
The key is the LOOKUP call. Given how it works, if its 1st argument is
greater than any value in its 2nd argument, it returns the last item in
its last argument with the same type as its 1st argument. Since strings
can't be longer than 32767 characters in Excel, 32768 is guaranteed to
be greater than any numeric value returned by FIND, so the LOOKUP
formula above returns FIND's last numeric result, which corresponds to
the position of the last / in A1. You could use any arbitrarily large
value as the 1st argument to LOOKUP.
>BTW I don't believe you need the +1 at the end
Sorry, the +1 advances you to the character position after the last /.
I was paying too much attention to other responses.
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