left()

[mpele]

Why the command

b=Left(poz, InStr(poz, "!") + 1)

is working and

b=Left(poz, InStr(poz, "!") - 1)

doesn't work? It say: Invalid procedure call or argument...

[Norman Jones]

Hi M,

If the exclamation character (!) is found, both expressions work for me.

If however, the character is not found, then the exptrssion:

InStr(poz, "!") - 1

equates to -1 which is an invalid in the Left function,


---
Regards,
Norman



"mpele" <[email protected]> wrote in
message news:[email protected]...
>
> Why the command
>
> b=Left(poz, InStr(poz, "!") + 1)
>
> is working and
>
> b=Left(poz, InStr(poz, "!") - 1)
>
> doesn't work? It say: Invalid procedure call or argument...
>
>
> --
> mpele
> ------------------------------------------------------------------------
> mpele's Profile:
> http://www.excelforum.com/member.php...o&userid=31808
> View this thread: http://www.excelforum.com/showthread...hreadid=520041
>

[Bob Phillips]

If it doesn't find ! in the string poz, then the Instr returns 0. Subtract 1
from that, and you are then trying to get the leftmost -1 characters. Hence,
it is invalid.

You should test it

if InStr(poz, "!")> 0 Then
b=Left(poz, InStr(poz, "!") - 1)
Else
b = poz
End If


--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"mpele" <[email protected]> wrote in
message news:[email protected]...
>
> Why the command
>
> b=Left(poz, InStr(poz, "!") + 1)
>
> is working and
>
> b=Left(poz, InStr(poz, "!") - 1)
>
> doesn't work? It say: Invalid procedure call or argument...
>
>
> --
> mpele
> ------------------------------------------------------------------------
> mpele's Profile:
http://www.excelforum.com/member.php...o&userid=31808
> View this thread: http://www.excelforum.com/showthread...hreadid=520041
>

[mpele]

[QUOTE=Norman Jones]Hi M,

If the exclamation character (!) is found, both expressions work for me.

InStr gives result 6 but I need value 5 for function left.
What am I doing wrong? or what can I do wrong?!?

[Norman Jones]

Hi M,

Your error is consistent with the exclamation character not being found.

If the expression:

InStr(poz, "!")

returns 6, as you suggest, I would not expect either of your original
expressions:

> b=Left(poz, InStr(poz, "!") + 1)
or
> b=Left(poz, InStr(poz, "!") - 1)

to produce your encountered error.


---
Regards,
Norman



"mpele" <[email protected]> wrote in message
news:[email protected]...
>
> Norman Jones Wrote:
>> Hi M,
>>
>> If the exclamation character (!) is found, both expressions work for
>> me.
>>
>> InStr gives result 6 but I need value 5 for function left.
>> What am I doing wrong? or what can I do wrong?!?
>
>
> --
> mpele
> ------------------------------------------------------------------------
> mpele's Profile:
> http://www.excelforum.com/member.php...o&userid=31808
> View this thread: http://www.excelforum.com/showthread...hreadid=520041
>