counting actual and displayed values

[lxrhee]

Hi guys,
I have a sheet with the following values, and certain cells are formatted differently.

0 - displays as 0
0 - displays as 0.0
0 - displays as 0.00
0.0043 - displays as 0.00
0.0043 - displays as 0.0
0.0043 - displays as 0.0043
1 - displays as 1
-0.1 - displays as -0.1

I realize that no matter how a number is formatted, excel retains the underlying value. I want the formatted value though. For this list of numbers, I want to count the cells where the underlying value is 0, and count the cells where the formatted value is 0, via a macro.
So in this example, there are 3 real 0s, and 5 formatted 0s.
I don't really want to convert to text or anything, I tried rounding as well but can't find a good solution. c.value and c.formula both look at the underlying value. Is there something I can use in a macro to get the displayed value, rather than the underlying value? THanks!

[Ardus Petus]

You can test Range("A1").Text for formatted text, and .Value for underlying
value.

HTH
--
AP

"lxrhee" <[email protected]> a écrit dans
le message de news: [email protected]...
>
> Hi guys,
> I have a sheet with the following values, and certain cells are
> formatted differently.
>
> 0 - displays as 0
> 0 - displays as 0.0
> 0 - displays as 0.00
> 0.0043 - displays as 0.00
> 0.0043 - displays as 0.0
> 0.0043 - displays as 0.0043
> 1 - displays as 1
> -0.1 - displays as -0.1
>
> I realize that no matter how a number is formatted, excel retains the
> underlying value. I want the formatted value though. For this list of
> numbers, I want to count the cells where the underlying value is 0, and
> count the cells where the formatted value is 0, via a macro.
> So in this example, there are 3 real 0s, and 5 formatted 0s.
> I don't really want to convert to text or anything, I tried rounding as
> well but can't find a good solution. c.value and c.formula both look at
> the underlying value. Is there something I can use in a macro to get
> the displayed value, rather than the underlying value? THanks!
>
>
> --
> lxrhee
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