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Help with countif using two columns

  1. #1
    Registered User
    Join Date
    08-17-2006
    Posts
    9

    Help with countif using two columns

    Hi, the answer to my problem is pobably obvious but i need help.

    I have a spreadsheet in which column B returns True or False values and column E returns true or false values .

    I would like to count the number of cells in which False appears in both columns in the same row, ie if b4 and e4 are both false, then it returns the value 1.

    The range is from rows 3 to 383.

    I have tried these formulas but they keep on returning 0.

    =SUMPRODUCT((b3:b383="FALSE"),(E3:E383="FALSE"))

    =SUMPRODUCT((CZ3:CZ383="FALSE")*(E3:E383="FALSE")).

    your help would be gratefully appreciated.
    Last edited by Vipulparbat; 08-17-2006 at 08:03 PM.

  2. #2
    Dave Peterson
    Guest

    Re: Help with countif using two columns

    If those values that are returned are really the Boolean TRUE and FALSE, then
    remove the double quotes:
    =SUMPRODUCT(--(b3:b383=FALSE),--(E3:E383=FALSE))
    or
    =SUMPRODUCT((CZ3:CZ383=FALSE)*(E3:E383=FALSE))

    But excel will treat empty cells as FALSE.

    You may want something like:
    =SUMPRODUCT(--(b3:b383<>""),--(b3:b383=FALSE),
    --(e3:e383<>""),--(e3:e383=FALSE))

    Adjust the ranges to match--but you can't use whole columns.

    =sumproduct() likes to work with numbers. The -- stuff changes trues and falses
    to 1's and 0's.

    Bob Phillips explains =sumproduct() in much more detail here:
    http://www.xldynamic.com/source/xld.SUMPRODUCT.html

    And J.E. McGimpsey has some notes at:
    http://mcgimpsey.com/excel/formulae/doubleneg.html


    Vipulparbat wrote:
    >
    > Hi, the answer to my problem is pobably obvious but i need help.
    >
    > I have a database in which column B returns True or False values and
    > column E returns true or false values .
    >
    > I would like to count the number of cells in which False appears in
    > both columns in the same row, ie if b4 and e4 are both false, then it
    > returns the value 1.
    >
    > The range is from rows 3 to 383.
    >
    > I have tried these formulas but they keep on returning 0.
    >
    > =SUMPRODUCT((b3:b383="FALSE"),(E3:E383="FALSE"))
    >
    > =SUMPRODUCT((CZ3:CZ383="FALSE")*(E3:E383="FALSE")).
    >
    > your help would be gratefully appreciated.
    >
    > --
    > Vipulparbat
    > ------------------------------------------------------------------------
    > Vipulparbat's Profile: http://www.excelforum.com/member.php...o&userid=37683
    > View this thread: http://www.excelforum.com/showthread...hreadid=572897


    --

    Dave Peterson

  3. #3
    Franz Verga
    Guest

    Re: Help with countif using two columns

    Vipulparbat wrote:
    > Hi, the answer to my problem is pobably obvious but i need help.
    >
    > I have a database in which column B returns True or False values and
    > column E returns true or false values .
    >
    > I would like to count the number of cells in which False appears in
    > both columns in the same row, ie if b4 and e4 are both false, then it
    > returns the value 1.
    >
    > The range is from rows 3 to 383.
    >
    > I have tried these formulas but they keep on returning 0.
    >
    > =SUMPRODUCT((b3:b383="FALSE"),(E3:E383="FALSE"))
    >
    > =SUMPRODUCT((CZ3:CZ383="FALSE")*(E3:E383="FALSE")).
    >
    > your help would be gratefully appreciated.


    Try with this:

    =SUMPRODUCT((BZ3:BZ383=FALSE)*(E3:E383=FALSE)).


    --
    Hope I helped you.

    Thanks in advance for your feedback.

    Ciao

    Franz Verga from Italy



  4. #4
    Registered User
    Join Date
    08-17-2006
    Posts
    9
    Thanks Franz, I'm sure I tried that but it didnt work before. It works fine now even though i quoted cells cz in my original post instead of e
    Last edited by Vipulparbat; 08-17-2006 at 08:59 PM.

  5. #5
    Franz Verga
    Guest

    Re: Help with countif using two columns

    Vipulparbat wrote:
    > Thanks Frank, I'm sure I tried that but it didnt work before. It
    > works fine now


    You're welcome. But... Who is Frank?


    --
    Hope I helped you.

    Thanks in advance for your feedback.

    Ciao

    Franz Verga from Italy



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