Series with noncontiguous unequal length data?

I have 12 months of data and an average of the 12 months that are in a
series on a chart. I reference the data using an offset formula.

I would like to move the average at the bottom of the column of data to
another column, but I don't know a way to still include that one cell
in the series with the 12 months of data in the original column.

Is there a way to do this?

Thanks for any advice!

Copy the cell that was moved.
Select the chart.
From the top menu goto Edit --> Paste Special...
Make sure New Points is selected in the pop up dialog box, and click OK.
That one point should be pasted to the end of your series.

-Simon

"[email protected]" wrote:

> I have 12 months of data and an average of the 12 months that are in a
> series on a chart. I reference the data using an offset formula.
>
> I would like to move the average at the bottom of the column of data to
> another column, but I don't know a way to still include that one cell
> in the series with the 12 months of data in the original column.
>
> Is there a way to do this?
>
> Thanks for any advice!
>
>

Thanks Simon, but I should have been clearer in my original post.

I'm trying to find a way to plot a series in a dynamic chart and what
is needed is a way to alter the offset formula in the named formula so
two ranges are referenced and included in the same series. Either that
or it happens in the chart reference as your solution suggests, but
maybe it could do this with another named formula for the additional
point at the end.


SimonCC wrote:
> Copy the cell that was moved.
> Select the chart.
> From the top menu goto Edit --> Paste Special...
> Make sure New Points is selected in the pop up dialog box, and click OK.
> That one point should be pasted to the end of your series.
>
> -Simon
>
> "[email protected]" wrote:
>
> > I have 12 months of data and an average of the 12 months that are in a
> > series on a chart. I reference the data using an offset formula.
> >
> > I would like to move the average at the bottom of the column of data to
> > another column, but I don't know a way to still include that one cell
> > in the series with the 12 months of data in the original column.
> >
> > Is there a way to do this?
> >
> > Thanks for any advice!
> >
> >

So sounds like you got the offset formula part taken care of for both the
regular points and the extra point. If I understand correctly, they are both
named ranges and represented by offset formula. I'm guessing you only need
to know how to put both named ranges in the same series? Hopefully I am
correct.

If that's the case, just right click chart to select Source Data...
In the Values box for the series, put:
=(Sheet#!Range1,Sheet#!Range2)
It's important to include the sheet name or else it won't work.

Hopefully I'm not answering the wrong question again. :p

-Simon

"[email protected]" wrote:

> Thanks Simon, but I should have been clearer in my original post.
>
> I'm trying to find a way to plot a series in a dynamic chart and what
> is needed is a way to alter the offset formula in the named formula so
> two ranges are referenced and included in the same series. Either that
> or it happens in the chart reference as your solution suggests, but
> maybe it could do this with another named formula for the additional
> point at the end.
>
>
> SimonCC wrote:
> > Copy the cell that was moved.
> > Select the chart.
> > From the top menu goto Edit --> Paste Special...
> > Make sure New Points is selected in the pop up dialog box, and click OK.
> > That one point should be pasted to the end of your series.
> >
> > -Simon
> >
> > "[email protected]" wrote:
> >
> > > I have 12 months of data and an average of the 12 months that are in a
> > > series on a chart. I reference the data using an offset formula.
> > >
> > > I would like to move the average at the bottom of the column of data to
> > > another column, but I don't know a way to still include that one cell
> > > in the series with the 12 months of data in the original column.
> > >
> > > Is there a way to do this?
> > >
> > > Thanks for any advice!
> > >
> > >
>
>