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I have ploted points, and used a log trendline. it give me an equations:
y= .802ln(x)+2.39
I can't remember how to use this to find y for points x.
is it correct to use:
=((.802)ln(x))+2.39
Thank you
=((.802)*ln(x))+2.39
how to use the log. trend line equation
I have ploted points, and used a log trendline. it give me an equations:
y= .802ln(x)+2.39
I can't remember how to use this to find y for points x.
is it correct to use:
=((.802)ln(x))+2.39
Thank you
=((.802)*ln(x))+2.39
Last edited by oddcarout; 07-20-2011 at 07:00 PM. Reason: Solved
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