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6000 X
5000 Y
2000 Y
3000 X
2500 Y
1280 X
3000 X
If column A with values and the column B with Letters,
please advise me how to find this..
if B1 is X, C1 will be 3% of A1, and if B1 is Y, C1 will be 2% of A1
If function to find % of a value
6000 X
5000 Y
2000 Y
3000 X
2500 Y
1280 X
3000 X
If column A with values and the column B with Letters,
please advise me how to find this..
if B1 is X, C1 will be 3% of A1, and if B1 is Y, C1 will be 2% of A1
=if( B1="X", A1*0.03, IF( B1="Y", a1*0.02, "B does not = Y or X"))
If you can only have a Y or an X in column B
this can be simplified to
=if( B1="X", A1*0.03, a1*0.02)
Wayne
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Hi,
a possible approach:
=A1*(B1="X")*3%+A1*(B1="Y")*2%
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Maybe:Formula:
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Regards, TMS
Trevor Shuttleworth - Retired Excel/VBA Consultant
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Slight variation on Canapone's formula:Formula:Please Login or Register to view this content.
His formula is good because, if column B is neither "X" or "Y" you will automatically get zero (0) returned.
Regards, TMS
Thank you very much.. it works...
This is also correct but, I dont get it.. thanks anyway..
Works thanks..Originally Posted by etaf
your welcome, thanks for the rep
this too works.. but i dont get it clearly.. never mind about my ability..thanks again..
That's awesome.. thanks bro..Slight variation on Canapone's formula:Formula:Please Login or Register to view this content.
His formula is good because, if column B is neither "X" or "Y" you will automatically get zero (0) returned.
Regards, TMS
That's awesome.. thanks bro..Slight variation on Canapone's formula:Formula:Please Login or Register to view this content.
His formula is good because, if column B is neither "X" or "Y" you will automatically get zero (0) returned.
Regards, TMS
You're welcome.
B1="X" will be TRUE if B1 contains the value "X". This will be evaluated as one (1) so, multiplied by 3% gives you 3% of A1. If B1 does not contain "X", it will be FALSE and evaluated as zero (0), and when multiplied by 3% gives you 0% of A1. Similarly, you compare to "Y". If B1 is not "X" or "Y", both equations will evaluate to 0.
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