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Compounding income with a reducing earning base

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    Compounding income with a reducing earning base

    I am trying to calculate what the total return would be over a defined period where there is a natural attrition rate from the base. Input fields are therefore (i) Starting earnings (ii) Time period (years) and (iii) attrition/retention rate. For example $100,000 starting earnings over five years with a 90% retention (10% attrition) per annum.

    I would have thought this would be straight forward however I have not found an obvious answer. Positive growth is easy: $100,000 x 5^(1+0.1).

    Any guidance would be greatly appreciated.

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    Re: Compounding income with a reducing earning base

    just a guess => is it not

    $100,000 x 1/( 5^(1+0.1))

    You did not add the desired result, so I could not test it.
    Notice my main language is not English.

    I appreciate it, if you reply on my solution.

    If you are satisfied with the solution, please mark the question solved.

    You can add reputation by clicking on the star * add reputation.

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    Re: Compounding income with a reducing earning base

    Thanks for the suggestion. I had a closer look at my increasing growth formula and it is wrong so ignore it. It had fields back to front and doesn't include the compounding element.

    Going back to the drawing board - what I need is a simple way to calculate:

    $100,000 + $100,000x(1-0.1) + $100,000x(1-0.1)^2 + $100,000x(1-0.1)^3 + $100,000x(1-0.1)^4 = $368,559.

    I need to be able to have a variable number of years (5 above), retention percentage (90% above) and earnings ($100,000 above) so managers can do a whatif analysis. The formula needs to generate the total over the period of time.
    Last edited by borderex; 02-16-2015 at 08:02 PM.

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    Re: Compounding income with a reducing earning base

    Quote Originally Posted by borderex View Post
    what I need is a simple way to calculate:
    $100,000 + $100,000x(1-0.1) + $100,000x(1-0.1)^2 + $100,000x(1-0.1)^3 + $100,000x(1-0.1)^4 = $368,559.

    I need to be able to have a variable number of years (5 above), retention percentage (90% above) and earnings ($100,000 above) so managers can do a whatif analysis. The formula needs to generate the total over the period of time.
    Let B1 be the retention rate (90%), B2 be the number of years (5), and B3 be the initial amount (100,000). The total after B2 years is:

    =FV(1-B1,B2,-B3,0,1)

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    Re: Compounding income with a reducing earning base

    Thanks. Problem solved. I needed to reverse the first field in the suggestion to B1-1 as the value is diminishing. The final formula is =FV(B1-1,B2,-B3,0,1).

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    Re: Compounding income with a reducing earning base

    Quote Originally Posted by borderex View Post
    I needed to reverse the first field in the suggestion to B1-1 as the value is diminishing. The final formula is =FV(B1-1,B2,-B3,0,1).
    Glad you caught my typo. I had originally written -10% as a constant, then made a mistake when I substituted "variables" in the posting, without testing.

    However, looking back, I wonder if my suggestion is still wrong.

    I gave you a formula (or tried to) that results in $368,559, given your parameters (-10%, 5, 100000).

    But your mathematical expression:

    $100,000 + $100,000x(1-0.1) + $100,000x(1-0.1)^2 + $100,000x(1-0.1)^3 + $100,000x(1-0.1)^4

    is equal to $409,510, not $368,559.

    The FV usage that matches your mathematical expression is:

    =FV(B1-1,B2,-B3)

    The 4th and 5th parameters are zero by default.

    PS.... The mathematical expression that results in $368,559 and matches my original FV usage (as corrected by you) is:

    100000*(90%)+100000*(90%)^2+100000*(90%)^3+100000*(90%)^4+100000*(90%)^5

    Only you can determine which mathematical expression and total you intended.
    Last edited by joeu2004; 02-17-2015 at 08:24 PM. Reason: PS

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    Re: Compounding income with a reducing earning base

    You are absolutely right. The first year should have been the full $100,000 rather than the 10% reduction occuring immediately. The formula gets easier each time I come back. Thanks again.

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