Index-Match, Reference Range Jumps 8 Rows if Dragged Down

[uckycool]

Hi members of excel forum..
I have an index-match formula in a cell of one table.
I want to fill the rows below that cell by using the formula of that cell (which is the index-match formula).
By dragging down the cell, as we know the below cells will be filled automatically jumping one row respectively.
However, my goal is to fill the below cells by a reference range that jumped several number of rows (8 to be precise).
For easier understanding, I attach the example sheet (pls see the comment box).
Thank you very much for your attention and assistance.

[benishiryo]

hi there. 2 possible methods:
=INDEX(D$6:D$45,MATCH($C49,$B$6:$B$45,0)+7)

or:
=INDEX(D$6:D$45,(ROWS(D$48:D49)-1)*8)

Edit: didn't realize it was for "LOB3". Phuocam's solution would work by adding a MATCH formula of "LOB3". but that is assuming the sequence is always the same as Dept 1. the same assumption can be used with this:
=INDEX(D$6:D$45,3+(ROWS(E$49:E49)-1)*8)

[Phuocam]

Try:

=INDEX(D$6:D$45,MATCH($C49,$B$6:$B$45,0)+MATCH("LOB 3",$C$6:$C$45,0)-1)

[uckycool]

Try:

=INDEX(D$6:D$45,MATCH($C49,$B$6:$B$45,0)+MATCH("LOB 3",$C$6:$C$45,0)-1)

Really sorry not replying to the replies since I re-arrange my table.
However, I've tried each solution given and formula from Phuocam works really well.
Thank you very much for the help!