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Split string with no delimiters to grab last word as numerical value in new column

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    Split string with no delimiters to grab last word as numerical value in new column

    I need a formula to extract the charge amount from text

    Chase bank only lets me download 90 days of transactions. To go further back, I am copy/pasting from older PDF statements and this is how it turns out:

    01/13 CHEWY.COM 800-6724399 FL 115.56
    01/14 AT&T*BILL PAYMENT 800-331-0500 TX 226.06
    01/15 AMAZON MKTPLACE PMTS AMZN.COM/BILL WA 21.89
    01/15 T.J. MAXX # 1228 CRANSTON RI 53.29
    01/15 TJMAXX #0315 WARWICK RI 239.50
    01/15 WHOLEFDS CRN 10254 CRANSTON RI 279.29
    01/16 NEW YORK TIMES DIGITAL 800-698-4637 NY 7.50

    I want to split this to three columns. One each for date, description, and amount.

    I am obviously able to use Text to Columns using fixed width to split the date from the rest. That creates two columns. Then I need to grab the dollar amount and split that to a 3rd column. I recorded a macro using my keyboard keys to edit, move the cursor backward to the final space character (^left-arrow 3x), then select to the end, cut the text, and paste. The VB created didn't capture my intent even closely, so I am back to using a formula.

    How can I create a 3rd column having only the transaction amount?

    Thanks Jamie

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    Re: Split string with no delimiters to grab last word as numerical value in new column

    Never mind. I ate some dinner, my IQ went up, and then did a much better Google Search on "select last word in excel" and it gave me this

    =TRIM(RIGHT(SUBSTITUTE(text," ",REPT(" ",100)),100))

    and it works great.

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    Re: Split string with no delimiters to grab last word as numerical value in new column

    another way:

    =-LOOKUP(1,-RIGHT(A1,{1,2,3,4,5,6,7,8,9,10}))

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    Re: Split string with no delimiters to grab last word as numerical value in new column

    Hi,

    The values and amount can be split out with the following in B1, C1 and D1. original string in A1

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    Richard Buttrey

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