I am learning Excel and I need to figure out how to count the amount of perfect meetings.

[Jeplonski]

I am trying to make it so that if the value of (P2:P73) = yes, and the value of (Q2:Q73) = no, it counts as 1 entity in L86. This is a little tough to explain because I can't explain the entire project I am working on as it is work-related. Essentially, say a meeting that was held went well, no issues, and it started in 60 seconds. I want to count every meeting that went off without any issues. So, if P2's value is "yes" and Q2's value is "no", L86's value will increase by 1, as it is showing 1 meeting that went perfect. Is there a way to use IF AND statements to achieve this?

I appreciate any help so thanks in advance! Also, I am new to this forum so let me know if my attachment did not go up. Most of the information is hidden in the screenshot for privacy reasons, but everything needed to answer this should be on there. Thanks so much

[MrShorty]

As you say, it is difficult to understand what you want.

What I see you describing sounds to me like a COUNTIFS() function: https://support.office.com/en-us/art...c-aa8c2a866842 Something like =COUNTIFS(P2:P72,"yes",Q2:Q72,"no") would count all of the records where column P is "yes" and column Q is "no". Is that what you are trying to do?

Edit to add: I could also see using a pivot table for counting different combinations: https://www.excel-easy.com/data-****...ot-tables.html If this is the kind of data you work with and the kind of analysis you are going to be doing, I expect that at some point you are going to want to learn pivot tables.

[Mark_G_]

I'd probalby add a new collumn to R, this would be =IF(P2="yes',IF(Q2="no",1))
Then do =COUNTIF(R:R,1)
That'll give you the number of lines that match your requirement. you could then take the average of this against your count of meetings for L86 if you wish.

[alansidman]

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