Hi
I am quite a novice at Excel formulas. Currently pulling my hair out. Could you help me with the following formula:
If L2 >= B2+10, then the value is L2, but IF L2 >B2+6 and L2<B2+10 then the value is L3, and IF L2< B2+6 then the value is L2+1.3
I've read help files, but the nesting is messing things up.
Please help.
Raz_M
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Hello and welcome to the forum.
Try this:
=IF(L2>=B2+10,L2,IF(AND(L2<B2+10,L2>=B2+6),L3,IF(L2<B2+6,L2+1.3)))
It can be shortened further but this layout is for your ease of understanding.
Shorter version:
=IF(L2>=B2+10,L2,IF(L2>=B2+6,L3,L2+1.3))
Last edited by 63falcondude; 10-22-2019 at 10:10 AM.
Try:
=IF(L2 >= B2+10,L2,IF(AND(L2 >B2+6, L2<B2+10),L3,IF(L2< B2+6,L2+1.3,"No condition yet")))
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Thank you!
If that takes care of your original question, please select Thread Tools from the menu link above and mark this thread as SOLVED.
If you have further queries on this, you need to continue here. I have closed the duplicate thread.
In answer to the Q posed on your duplicate (and now closed) thread:
=IF(ABS(B2-L2)<6,L2-1.3,IF(ABS(B2-L2)<10,10*LOG((10^(L2/10))-(10^(B2/10))),L2))
Glenn
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Temporary addition of accented to illustrate ongoing problem to the TT: L? fh?ile P?draig sona dhaoibh
Hi
I posted here on Tuesday, but have been away. Only just had a chance to have a go with this, and I'm still struggling.
The purpose of the calc is for a calculation sheet which simply compares values:
* If the difference between L2 and B2 is >=10, then the value is L2.
* If the difference between L2 and B2 is >=6 AND <10, then the value is the logarithmic equation
* If the difference between L2 and B2 is <6, then there is a simple subtraction of 1.3 from L2
Here's the formula I am using: =IF(L2-B2>=10,L2,IF(L2-B2<6,L2-1.3,IF(AND(L2-B2>6,L2-B2<10),10*LOG((10^(L2/10))-(10^(B2/10))))))
When I use real data, the above corrections do not seem to work. So, I am sure I have done something fundamentally wrong. I'm just not experienced enough to figure it out. Can any of you experts help?
Many thanks, for what must seem ultra-trivial.
Raz
My answer is given in Post 8 of this thread. I'm faster than light, you know!!
If incorrect, then post a sample sheet with manually calculated answer examples.
Hi,
Thanks. I'm using this now: IF(ABS(L2-B2)<6,L2-1.3,IF(ABS(L2-B2)<10,10*LOG((10^(L2/10))-(10^(B2/10))),L2)) Apologies about the confusion of the L2 and B2 order! This works, except for when L2-B2 is equal to '10'. So for L2 =100 and B2 =90, the formula spits out 99.5 instead of 100. Any idea?
Thanks again.
Maybe this:
=ROUND(IF(ABS(L2-B2)<6,L2-1.3,IF(ABS(L2-B2)<10,10*LOG((10^(L2/10))-(10^(B2/10))),L2)),0)
Hi
Thanks, no that doesn't seem to solve it. Also, I need to work to 2 decimal places.
Please attach a sample workbook - we've reached the limit of working in the dark. We need to see this in context. See the yellow banner up top or post #2 for instructions.
Last edited by AliGW; 10-27-2019 at 05:55 AM.
Waiting for the workbook ... Hope you are putting one together for us.
Hi
Excel sheet attached. The sheet averages lots of data for L2 and B2 and then applies the calc. As seen in Case 1, a difference of 10 returns 99.5 instead of 100.
Thanks again, Raz
Hi ,
This may or may not be relevant , but in the formulae that you use , you have :
1. =COUNT(D2,D4,D5,D6,D7,D8,D9,D10,D11,D12,D13,D15,D16,D17,D18,D19,D20,D21,D22,D23,D24,D25,D16)
2. =COUNTA(E2,E4,E5,E6,E7,E8,E9,E10,E11,E12,E13,E15,E16,E17,E18,E19,E20,E21,E22,E23,E24,E25,E16)
3. =COUNT(D31,D33,D34,D35,D36,D37,D38,D39,D40,D41,D42,D44,D45,D46,D47,D48,D49,D50,D51,D52,D53,D54,D45)
4. =COUNTA(E31,E33,E34,E35,E36,E37,E38,E39,E40,E41,E42,E44,E45,E46,E47,E48,E49,E50,E51,E52,E53,E54,E45)
In all the cases in the denominator , two cell values have been omitted , while one cell value has been repeated.
Is this intentional ? At present , this will not matter , but as and when those omitted / repeated cells have data , it can make a difference.
Narayan
Hi
May have changed when I deleted several other rows to make this a sheet i can share. But thank you for pointing this out to me, very appreciated.
Hi ,
Can you not use the shorter versions which use the colon , as in :
=COUNT(D2:D26)
Since D14 does not contain any data , including it will not make any difference.
The shorter version is easier to read and understand.
Narayan
From D29:
=IF(ABS(D28-D57)<=6,D28-1.3,IF(ABS(D28-D57)<10,10*LOG((10^(D28/10))-(10^(D57/10))),D28))
Explain the ranges you have used - these make no sense to me in the context.
Hi
Many thanks for your help to date. The ranges apply a correction to measured noise data (L2), depending on how noisy background levels are (B2).
That's what they are meant to do, but have you actually CHECKED that those ranges are correct? They certainly don't appear to be based on your sample file. For instance: D28-D57????
Hi Thanks for your help with this. I will try to resolve this formula offline. I had (wrongly) assumed there was a simple way that excel could test three different conditions and apply a result based on the outcome of each test.
Thanks again.
I did not say that what you want to do cannot be done - how did you get that from what I posted???
We would like to help you to solve this - you just need to answer questions carefully and give any other details requested.
If that takes care of your original question, please select Thread Tools from the menu link above and mark this thread as SOLVED.
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