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Counting data duplicates across columns

  1. #1
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    Unhappy Counting data duplicates across columns

    Hello Friends,

    I am seeking your help after trying several things.

    Problem : I have an excel sheet for everyday data across columns.

    So Column A will have a set of data -> Alan, Bosch, Case, Dodge, Elan, Fiama and so on (around 50) for 01st Jan
    Column B will have a set of data -> Aron, Bell, Carol, Dodge, Eric and so on (around 50) for 02nd Jan....
    Similarly Column C, D, E, etc. for a month.

    There can be common data across the columns as in the above case it is Dodge.

    I want to find the number of occurrence of any data without searching for that particular data. Count will only work if I know what I want to count.

    I want 2 separate columns one with the data and the next indicating the number of occurrences. So if Dodge appears on 01st Jan, 02nd Jan, 10th Jan and 20th Jan then I have something like ->
    Dodge 4

    and so on.

    Look forward to your help and thanking you in advance.

  2. #2
    Forum Expert dilipandey's Avatar
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    Re: Counting data duplicates across columns

    HI sahsinha,

    welcome to the forum.

    Try using below formula:-

    Formula: copy to clipboard
    Please Login or Register  to view this content.


    see attached:- counting data duplicates.xlsx


    Regards,
    DILIPandey
    <click on below * if this helps>
    DILIPandey, Excel rMVP
    +919810929744 (India), +971528225509 (Dubai), [email protected]

  3. #3
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    Re: Counting data duplicates across columns

    Hello Mr. Pandey,

    Thanks a ton for your help.

    Frankly I lost hope that anyone would reply - but you have indeed been very kind.

    Cheers,
    Sahil

  4. #4
    Forum Expert dilipandey's Avatar
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    Re: Counting data duplicates across columns

    You are welcome Sahil... cheers


    suggest you to mark this thread as [SOLVED]. Thanks.


    Regards,
    DILIPandey
    <click on below * if this helps>

  5. #5
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    Re: Counting data duplicates across columns

    Done - marked as solved. :-)

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