This works better. Insert a column of zeros like this:
|
A |
B |
C |
D |
E |
F |
G |
2 |
|
|
Tier1 |
Tier2 |
Tier3 |
Tier4 |
Tier5 |
3 |
A1 |
0 |
£99 |
£199 |
£299 |
£399 |
£5,000 |
4 |
A2 |
0 |
£49 |
£99 |
£199 |
£299 |
£500 |
5 |
A3 |
0 |
£99 |
£199 |
£299 |
£399 |
£1,000 |
6 |
A4 |
0 |
£99 |
£199 |
£299 |
£399 |
£1,000 |
7 |
A5 |
0 |
£99 |
£199 |
£299 |
£399 |
£1,000 |
8 |
B1 |
0 |
£299 |
£599 |
£999 |
£1,999 |
£10,000 |
9 |
B2 |
0 |
£99 |
£199 |
£299 |
£399 |
£1,000 |
10 |
B3 |
0 |
£99 |
£199 |
£299 |
£399 |
£1,000 |
Then, enter this in Sheet1!AE2 and fill down
A bit of an explanation:
Start in the middle and work outwards
INDEX(Sheet2!$B$3:$G$10,MATCH(AD2,Sheet2!$A$3:$A$10,0),0) This INDEX Sheet2!$A$3:$G$10 contains
all the rows and columns of data. So, a ROW and COLUMN has to be determined. This part of the formula returns the row number as in a "normal" formula.
When surrounded by MATCH(N2,......,1) This is in the COLUMN element of the first INDEX.
Therefore MATCH(N2,INDEX(Sheet2!$B$3:$G$10,MATCH(AD2,Sheet2!$A$3:$A$10,0),0),1) returns the column number of the value of N2.
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