Find Exact Number from a String in cell (InStr(13,"1.2.13.4") >> gives 6 i/o 0)

Good Day all

struggling this issue for a couple of hours....
It a rather small issue but could not figure out how to solve it.

In one cell I have a string such as 1.2.3.4 and i want to find if this string contains a number appear in other cell, lets say cell $A$1 = 3.
I’ve able to do it with Instr(A1,”1.2.13.4″)...OR with Search Formula, BUT

The problem is when i have a string such as: 1.2.13.4 , it "looks" on the 3 (remember...on cell $A$1) and returned 6 , as if this number is part of the string.
But i want to check if string contain 13 NOT 3.

Any help will be appreciated !!!

Posted as well on: http://www.ozgrid.com/forum/showthread.php?t=201899
and on: http://vbaf1.com/q/a/check-if-string-in-a-cell/
Shlomi

Your post does not comply with Rule 8 of our Forum RULES. Do not crosspost your question on multiple forums without including links here to the other threads on other forums.

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Add a . at the beginning and end of your string; so 1.2.3.4 becomes .1.2.3.4. Then search for "."&$D$1&"." in that string, assuming D1 contains the number you're searching for,. It'll find 3 but not 13.

So, with data starting in A1:

=SEARCH("."&$D$1&".","."&A1&".")

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