Hi there,
I have a list of amounts in a column from £10,000 to say £20. I need to express in another column the amount after a £1,500 cap? What's the formulae please?
Thx
Hi there,
I have a list of amounts in a column from £10,000 to say £20. I need to express in another column the amount after a £1,500 cap? What's the formulae please?
Thx
Hi,
If you mean you want to know the sum of the numbers above £1500 then
Formula:Please Login or Register to view this content.
If you mean something else then upload an example and tell us what result you expect.
Richard Buttrey
RIP - d. 06/10/2022
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Thanks!
What I was trying to get to was:
- in column B the c30,000 rows of sales amounts with a range of £20-10,000
- in cell A1 an entry of £1,500 (or another amount for modeling/sensitivity scenarios)
- In column C the sales amount: actual if <£1,500; or capped/expressed as £1,500 (or whatever value in A1
Thx
Last edited by perinouk; 01-28-2017 at 08:57 AM. Reason: removal of name
Are you saying that you just want to SEE the values in column B that are less than the value in A1?
If so why not just Autofilter column B.
If you want to extract the subset <A1 then use an Advanced Data filter.
Thanks!
I would like the sale value if ness than A1, or if greater, the value in A1
If I understand correctly the following formula will populate column C with the values you wish:Let us know if you have any questions.Formula:Please Login or Register to view this content.
Consider taking the time to add to the reputation of everybody that has taken the time to respond to your query.
Perhaps this will do
Data Range
A B C D 1 1500 2 Original Capped Amount 3 715 715 =MIN($A$1,B3) 4 4047 1500 5 1004 1004 6 2146 1500 7 7169 1500 8 7377 1500 9 9605 1500 10 9973 1500 11 4860 1500 12 863 863 13 3596 1500 14 3469 1500 15 245 245 16 5654 1500 17 439 439 18 2108 1500
<---------If you like someone's answer, click the star to the left of one of their posts to give them a reputation point for that answer.Ron W
Perfect!!! Thank you JeteMc.
You're Welcome and thank you for the feedback. I would be remiss if I didn't point out that newdoverman's MIN function yields the same values and probably uses less time/computing power. Please take a moment to mark the thread as 'Solved' using the thread tools link above your first post. I hope that you have a blessed day.
@JeteMc
Thank you for the mention.
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