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Find failling me!

  1. #1
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    Find failling me!

    Folks, I need help - I have the following that I would like to separate the number from the letter, but it's dropping a letter for one row (highlighted, with problem in cell C3 - could someone please help!
    Attached Files Attached Files

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    Re: Find failling me!

    FIND returns the position where it occurs. You just got lucky that the first two examples have 7 character numbers (including the space) and 7 character strings. As soon as your number was shortened, and the space character is now found at position 5, so RIGHT is returning the 5 right hand characters. If you add or remove characters in the top two examples, you'd see the problem is there, too, just hidden.
    You need to subtract the LEN of the string from the result of the find to yield the proper value for RIGHT.
    Pauley
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    Re: Find failling me!

    Yes! Thanks Pauleyb - if anyone needs, here's the formula for that cell =RIGHT(A3,LEN(A3)-FIND(" ",A3))

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    Forum Guru AlKey's Avatar
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    Re: Find failling me!

    Try this
    Enter formula in B1 and drag formula across to C1 and down
    Formula: copy to clipboard
    Please Login or Register  to view this content.

    v A B C
    1 30.848 EHash/s 30.848 EHash/s
    2 222.93 THash/s 222.93 THash/s
    3 4.817 EHash/s 4.817 EHash/s
    If you like my answer please click on * Add Reputation
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  5. #5
    Administrator FDibbins's Avatar
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    Re: Find failling me!

    Thanks for showing us that. There are obviously many ways of getting the same answers in excel, here are some more options...
    B1=--LEFT(A1,FIND(" ",A1))
    C1=MID(A1,FIND(" ",A1)+1,99)

    This assumes that that space will always be there to split the text and number
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  6. #6
    Administrator FDibbins's Avatar
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    Re: Find failling me!

    Thanks for the feedback

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