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power function

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    power function

    Need help with a formula

    231 in³ / ((3018 / 360) / 0.006944 ft²) can a formula be created from this?
    Last edited by jamboree; 01-29-2019 at 05:26 PM.

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    Forum Expert ben_hensel's Avatar
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    Re: Help with a formula

    Your post does not comply with Rule 1 of our Forum RULES. Your post title should accurately and concisely describe your problem, not your anticipated solution.

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    Forum Expert ben_hensel's Avatar
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    Re: power function

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    That's it, right?

    Yields 0.191 in some mixed in3*ft2 five-dimensional mixed-unit thing.

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    Re: power function

    this looks more likely to match what was written =231^3/((3018/360)/0.006944^2)
    though I am scratching my head as to why you are taking cubic inches and dividing by square feet, seems there should be some conversion first.
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    Forum Expert shg's Avatar
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    Re: power function

    I'd write it as

    =231 / 144 * 360 / 3018

    231/144 is the height of a gallon of liquid on a one-foot square base. Dunno what the rest of it is.
    Last edited by shg; 01-29-2019 at 07:23 PM.
    Entia non sunt multiplicanda sine necessitate

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    Re: power function

    Thanks for the help. I'm trying to figure how much wastewater is being applied on a spray system. Actual calculated precipitation rate (in/day)

    231 in³/((3018/360)/0.006944 ft²) 231 cubic inches per gallon/((sq ft area covered/360 gallons per day)/0.006944 sq ft.

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    Forum Expert shg's Avatar
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    Re: power function

    All sorted?

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    Re: power function

    I don't think so, I'm trying to look up some more info. I will let you know if I have it figured out. Thanks

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    Re: power function

    The formula in post #5 doesn't return what you'd expect?

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    Re: power function

    I apologize I must not have looked at it correctly. Yes it did come up with the answer I was looking for. Thank you for the help.

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    Forum Expert shg's Avatar
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    Re: power function

    You're welcome.

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    Forum Expert shg's Avatar
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    Re: power function

    You might set it up like this:

    A
    B
    C
    D
    1
    Area
    3018
    ft^2
    2
    Volume
    360
    gal
    3
    Depth
    0.19
    in B3: =B2 * 231 / (B1 * 144)

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    Re: power function

    thanks for the assistance

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