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Maths Stats Assistance

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    Maths Stats Assistance

    Hello, please can any of your clever people help me out with where I am going wrong with the attached speadsheet.

    I am trying to use standard deviation techniques to compare the quality of products.

    Hope to hear, thank you in advance!
    Attached Files Attached Files

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    Re: Maths Stats Assistance

    Could you just please check that your forum profile is up-to-date? Thanks.
    Ali


    Enthusiastic self-taught user of MS Excel who's always learning!
    Don't forget to say "thank you" in your thread to anyone who has offered you help.
    You can reward them by clicking on * Add Reputation below their user name on the left, if you wish.

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    Re: Maths Stats Assistance

    Oh, how do I do that please.....?

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    Re: Maths Stats Assistance

    It's the data listed under your name in each of your posts.

    If you are not familiar with how to update your profile find the dark blue menu at the top of this page that says
    Forum Actions
    . Click that and 'Edit Profile'.
    Dave

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    Re: Maths Stats Assistance

    Thank you for that, I have updated what I can, are you able to confirm I am up to date now please?

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    Re: Maths Stats Assistance

    Could you tell more about your worksheet? What and where are your expected results>?
    Quang PT

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    Re: Maths Stats Assistance

    Hi, the expected results are over in the far right columns, I am hoping someone who understands how these equations for 'mean' and 'standard deviation' would be able to tell me where I was going wrong with my formulas?!?

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    Re: Maths Stats Assistance

    Working out measures from a summary table will usually give different answers, which are less accurate, as you are basing the results on the midpoints of each range and not the actual values. However they are usually close.


    Although your formula are over compicated =SUM(J6/F6) is the same as =j6/f6 they are correct for the mean 43.8 is close to 43.95

    the SD formula is wrong it should be =SQRT((K6-(F6*E8*E8))/F6)
    2.42 is close to 2.97

    likewise the second mean is correctly calcuated but sd should be
    =SQRT((K14-(F14*E16*E16))/F14)

    which is 2.45 close to 2.47

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    Re: Maths Stats Assistance

    Quote Originally Posted by voniom View Post
    Thank you for that, I have updated what I can, are you able to confirm I am up to date now please?
    Yes, thanks.

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    Re: Maths Stats Assistance

    Hi, thank you for your clear explanation, this helps a lot thank you!
    Would you mind telling me how I could get the accurate answers not using a table.
    How would you use a 'frequency' figure in this instance? It would nice to be accurate!

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    Re: Maths Stats Assistance

    Fabulous, thank you, stay safe!

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    Re: Maths Stats Assistance

    You, too. No TT this year, I guess?

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    Re: Maths Stats Assistance

    To get the accurate figures you always calculate from the raw data, then you just need the average and stdev functions, looking at all the data.

    Any grouping of data to anything but unique values means you will get a less accurate figure

    if the raw data was 1, 2, 2, 4, 5, 6, 6, 8, 9
    You would get a mean of 4.77 and sd of 2.77


    in a table of

    Value Frequency
    1 1
    2 2
    4 1
    5 1
    6 2
    8 1
    9 1


    You would get exactly the same results, but once you start summarising to midpoints, you lose detail
    midpoint freq
    1-2 1.5 3
    3-4 3.5 1
    5-6 5.5 3
    7-8 7.5 1
    9-10 9.5 1

    average is now 4.61
    sd is now 2.84
    Last edited by davsth; 05-28-2020 at 04:22 AM.

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    Re: Maths Stats Assistance

    Sorry only just seen that you messaged me again, yeah all off this year :-( roll on next year :-)

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