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Last edited by Dom.Knight; 05-12-2021 at 08:33 AM.
One way
=SUMIFS(Data!K:K,Data!P:P,A21,Data!E:E,B21,Data!F:F,C21)/SUMIFS(Data!L:L,Data!P:P,A21,Data!E:E,B21,Data!F:F,C21)
Richard Buttrey
RIP - d. 06/10/2022
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Hello and thanks that does return the correct result. However if i drag up or down some of the other results it produces are not quite correct.
Example if i drag it up to H11 the result should be same as cell G11, F11 £2.22 But returns £8.89
Why?Originally Posted by Dom.Knight
There is only one record for Haddock Grade 1 on row 108. This is priced at £100 for 11.25 Kg = £8.89 /Kg
Ah ok i see the error not sure how to correct it thoe. The price £100 is based on a full box for 45kilos (£2.22 Kilo) but in fact it was only a 1/4 box (11.25Kilos)
A start is for you to explain in english how you would treat it. Does it apply to any partial box?
In that case
=SUMIFS(Data!K:K,Data!P:P,A11,Data!E:E,B11,Data!F:F,C11)/SUMIFS(Data!L:L,Data!P:P,A11,Data!E:E,B11,Data!F:F,C11)*SUMIFS(Data!L:L,Data!P:P,A11,Data!E:E,B11,Data!F:F,C11)/SUMIFS(Data!G:G,Data!P:P,A11,Data!E:E,B11,Data!F:F,C11)
That works correctly.
And sheet "Data" is a helper sheet, Column K is the price per full box, when entered on sheet "Market" a box may not always be a full so inturn will be marked as 0.25/ 0.5 or 0.75. In retrospect i shoud install another helper column in "Data" to show that
Yes, I was going to mention that you use a helper column in the data to record the percentage of a full box weight and incorporate that column to cut down on the current formula.
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