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RE: Counting groups of exact numbers in a huge list (column)

  1. #1
    pgiessler
    Guest

    RE: Counting groups of exact numbers in a huge list (column)

    This formula has been a great help to me. Thanks for the post; however what
    if the items have an alpha-numeric coding (like automobile license plates)?
    Is there an easy way to count unique labels in a list when the data in in a
    text format?

    Thanks

    "tjtjjtjt" wrote:

    > If they are all numbers:
    > =SUM(IF(FREQUENCY(A1:A11,A1:A11)>0,1))
    >
    > You can see this page for variations and details:
    > http://support.microsoft.com/kb/q268001/
    >
    > The formula is an Array, so you should press Ctrl+Shift+Enter to finish it.
    >
    > tj
    >
    > "*Jarom*" wrote:
    >
    > > I need to know how I can write a formula to count a very big list of numbers
    > > and return the total number of numbers that are different in the list. For
    > > example:
    > > 8800719
    > > 8800718
    > > 8800718
    > > 8800717
    > > 8800719
    > > 8800715
    > > 8800719
    > > 8800715
    > > As you can see there are 8 numbers in this list but of those 8 there are
    > > only 4 different case numbers. So if I had a list of several hundred or
    > > thousand case numbers like the ones above, and many of them had duplicates
    > > somewhere in the list, how can I get excel to give me a total number of all
    > > the similar case numbers?


  2. #2
    Bob Phillips
    Guest

    Re: Counting groups of exact numbers in a huge list (column)

    =SUMPRODUCT((A1:A11<>""(/COUNTIF(A1:A11,A1:A11&""))

    --
    HTH

    Bob Phillips

    (replace somewhere in email address with gmail if mailing direct)

    "pgiessler" <[email protected]> wrote in message
    news:[email protected]...
    > This formula has been a great help to me. Thanks for the post; however

    what
    > if the items have an alpha-numeric coding (like automobile license

    plates)?
    > Is there an easy way to count unique labels in a list when the data in in

    a
    > text format?
    >
    > Thanks
    >
    > "tjtjjtjt" wrote:
    >
    > > If they are all numbers:
    > > =SUM(IF(FREQUENCY(A1:A11,A1:A11)>0,1))
    > >
    > > You can see this page for variations and details:
    > > http://support.microsoft.com/kb/q268001/
    > >
    > > The formula is an Array, so you should press Ctrl+Shift+Enter to finish

    it.
    > >
    > > tj
    > >
    > > "*Jarom*" wrote:
    > >
    > > > I need to know how I can write a formula to count a very big list of

    numbers
    > > > and return the total number of numbers that are different in the list.

    For
    > > > example:
    > > > 8800719
    > > > 8800718
    > > > 8800718
    > > > 8800717
    > > > 8800719
    > > > 8800715
    > > > 8800719
    > > > 8800715
    > > > As you can see there are 8 numbers in this list but of those 8 there

    are
    > > > only 4 different case numbers. So if I had a list of several hundred

    or
    > > > thousand case numbers like the ones above, and many of them had

    duplicates
    > > > somewhere in the list, how can I get excel to give me a total number

    of all
    > > > the similar case numbers?




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