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Maximum accural

  1. 09-14-2010, 02:43 PM #1
    Reddog101
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    Maximum accural

    Accural need to put a max to be reached

    Currently have =Round(F15/F13,10)

    Thank you
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  2. 09-14-2010, 02:56 PM #2
    shg
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    Re: Maximum accural

    Pardon ?
    Entia non sunt multiplicanda sine necessitate
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