Value of X Axis at Point of intersection of graph

can any 1 help me out with the solution for getting the value of x axis as a output at the point of intersection of graph.
Line A Xvalues Yvalues Line B Xvalues Yvalues
0.00 0 0.00 0
10.00 13.16034096 36.37 82.25832595
15.00 20.52397047 40.00 115.8194413
20.00 28.4946725 43.64 134.3326777
25.00 37.13602193 47.28 138.9411748
30.00 46.51159363 50.91 148.3278756
35.00 56.68496247 54.55 157.8096965
40.00 67.71970333 58.19 160.7829491
45.00 79.67939109 61.82 162.5015485
50.00 92.62760063 65.46 163.047185
55.00 106.6279068 69.10 163.3801609
60.00 121.7438845 72.73 164.1433416
65.00 138.0391086 76.37 165.1955453
70.00 155.577154
75.00 174.4215955
80.00 194.636008
85.00 216.2839664
90.00 239.4290456
95.00 264.1348205
100.00 290.4648658

eg.xlsx

I generally think of two generic approaches to this kind of problem. Choose which approach you want to use, and we can help you implement it.

1) Curve fitting/regression: a) Select a suitable equation for each curve. b) regress coefficients for each curve using suitable regression routines. If the equations chosen in (a) are "linear," then we can use the LINEST() function to find those coefficients. If there are non-linear parameters, then we will have to use Solver or similar to get the coefficients. c) With usable equations for each curve, we now have a system of equations for which we need to find the solutions. So we pull out our algebra text and remember how to solve systems of equations (I like this tutorial http://www.purplemath.com/modules/syseqgen.htm).

2) Sometimes, rather than finding a single pair of equations that describes the entire data set, it is easier to define each curve as a collection of straight lines connecting the individual data points. This is called linear interpolation. This approach looks like this: a) Locate the interval for each curve that contains the intersection point. b) Use the boundary points for that interval for each equation to find slope and intercept for each curve over that interval. This can be accomplished using a combination of the MATCH(), INDEX(), and LINEST() (or SLOPE() and INTERCEPT()) functions. c) As before, with the coefficients of these two straight lines, you can solve the system of equations.

Choose an approach and we'll help you program it in.