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Indicate shift type coresponding to the time of day in a cell...

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    Indicate shift type coresponding to the time of day in a cell...

    I have 3 possible shifts: Day, Evening & Night.
    Days are 7:45-16:00, Evenings are 15:45-24:00 and Nights are 23:45-8:00.
    I want a formula that will tell me what shift an employee works based on the start time.

    eg.
    D3=7:45 AM, F3=4:00 PM (this is a day shift)
    D4=3:45 PM, F4=12:00 AM (this is an evening shift)
    D5=11:45 PM, F5=8:00 AM (this is a night shift)

    How can I get Cell I3 to display the word "Day" or "Evening" or "Night" properly?

    I have attached a sample sheet.

    thanks.
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    Last edited by Alwpg; 01-02-2012 at 07:28 AM.

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    Forum Contributor arlu1201's Avatar
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    Re: Indicate shift type coresponding to the time of day in a cell...

    Maybe you can attach a sample workbook so we can see in what formats the values are stored in columns D & F.
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    Re: Indicate shift type coresponding to the time of day in a cell...

    Quote Originally Posted by Alwpg
    I have 3 possible shifts...How can I get Cells I1, I2, I3 to display the word "Day" or "Evening" or "Night"?
    Assuming your start times are always one of those three values (as implied)

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    Re: Indicate shift type coresponding to the time of day in a cell...

    as you indicated, that will only work if the start time is exactly 7,15 or 23. I would also like to know the same info if the shift starts a couple hours late, for example.

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    Re: Indicate shift type coresponding to the time of day in a cell...

    Perhaps:

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    Re: Indicate shift type coresponding to the time of day in a cell...

    That works great, thanks. Only one thing...I don't have a clue what it is doing. Would you mind briefly explaining what it is doing?

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    Re: Indicate shift type coresponding to the time of day in a cell...

    In XL Time is a Decimal value (1 = 24 hours, e.g 6:00 = 0.25).

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    converts the time units such that an hour becomes 1 rather than 1/24 - e.g 6:00 [0.25] -> 6.0

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    above subtracts 7:45*24 from the resulting value (7:45 being the start of the first shift), e.g:

    7:30 -> 7.5 -> 0

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    it is obvious that given the subtraction where the start time < 7:45 we will end up with a negative value and MOD ensures we end up with appropriate remainder, e.g:

    7 -> -0.5 -> 23.5

    Given the subtraction of 7:45 from our start time we know the "times" of interest become:

    07:45 -> 00:00 -> 0
    15:45 -> 08:00 -> 8
    23:45 -> 16:00 -> 16

    For each of the above we have a distinct return type so we add a result_vector so instead of returning 8 we return "Evening" etc...

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