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Calling Application.NORM.S.DIST issue???

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    Calling Application.NORM.S.DIST issue???

    I have written the following functions and when I try to evalute it I get #Value in excel. For a test you can use S = 50, K = 60, T = 0.25, R = 0.05, V = 0.3, B = 0.01

    I started having trouble when I tried to use the excel function NORM.S.DIST()

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    Re: Calling Application.NORM.S.DIST issue???

    I think you are calling the function incorrectly. I think you need to use the "worksheet functions" collection of the application object. Follow instructions here: http://msdn.microsoft.com/en-us/libr...ice.15%29.aspx and follow the link to the list of worksheet functions available to visual basic. It appears that norm.s.dist function called from VBA uses underscores for the dots.
    Quote Originally Posted by shg
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    Re: Calling Application.NORM.S.DIST issue???

    Ahh the underscores fixed it. The difference between application and worksheet functions is with the error handling: http://www.cpearson.com/excel/callin...ionsinvba.aspx

    Thank you for the help.

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    Re: Calling Application.NORM.S.DIST issue???

    I think it might be called using:
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    But I've never used it and my Excel 2010 machine is switched off right now

    Regards, TMS
    Trevor Shuttleworth - Excel Aid

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    Re: Calling Application.NORM.S.DIST issue???

    TMS -- I think the difference between the NORMSDIST and NORM.S.DIST (NORM_S_DIST) functions is the latter is the 2010+ implementation. I cannot test them extensively, but they should be essentially the same function. Excel help claims that the newer versions of these functions use improved algorithms to calculate the same quantity. The main questions would probably be around whether you need backwards compatibility to pre 2010 or if you are more of a "forward thinking" programmer and in the mood to abandon all older implementations.

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    Re: Calling Application.NORM.S.DIST issue???

    @MrShorty: thanks for the insight. As you might be able to tell, I've never needed to use the function in any of its incarnations.

    Cheers, TMS

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