Getting the values of the points in a trendline

[[email protected]]

Hi,

Based on a set of data, I've created a line pivot chart in Excel. I
have added a trendline, wich works perfectly! So, why this question?

Is it possible to get the specific values of a certain point on the
trendline? For example:


Pivot table:

[AverageUse]
Month Percentage
1 10,1234%
2 12,4678%
3 9,4373%

Now I've create a pivot chart (that's a bit difficult to reproduce with
ASCII-art and added a trendline, now I would like to see my pivot
table like this:

[AverageUse]
Month Percentage TrendlinePercentage
1 10,1234% 9%
2 12,4678% 13%
3 9,4373% 9%


Wich excel-guru has some briliant ideas?

Thanks in advance,

Best Regards,

Alain

[K Dales]

Unfortunately (as far as I know) Excel does not give you easy access to the
trendline formula or its coefficients. You can, of course, calculate these
yourself but since we know Excel has calculated them already (after all, you
can choose to display the formula) it would be nice if the Trendline object
had a .Formula property that could be used.

But the best solution is to calculate them yourself from the chart's data
series. For info on the formulas there is a handy reference here:
http://j-walk.com/ss/excel/tips/tip101.htm
--
- K Dales


"[email protected]" wrote:

> Hi,
>
> Based on a set of data, I've created a line pivot chart in Excel. I
> have added a trendline, wich works perfectly! So, why this question?
>
> Is it possible to get the specific values of a certain point on the
> trendline? For example:
>
>
> Pivot table:
>
> [AverageUse]
> Month Percentage
> 1 10,1234%
> 2 12,4678%
> 3 9,4373%
>
> Now I've create a pivot chart (that's a bit difficult to reproduce with
> ASCII-art and added a trendline, now I would like to see my pivot
> table like this:
>
> [AverageUse]
> Month Percentage TrendlinePercentage
> 1 10,1234% 9%
> 2 12,4678% 13%
> 3 9,4373% 9%
>
>
> Wich excel-guru has some briliant ideas?
>
> Thanks in advance,
>
> Best Regards,
>
> Alain
>
>

[Peter T]

Look into Linest or better still various post by David Braden on the
subject.

If you particularly want to replicate your own trendline's formula you could
try something like this - parses the formula of trendline(1) in series 1 to
a cell formula.

start by selecting a cell offset one to right of the first value you want to
calculate

Sub GetFormula1()
Dim sFormula As String
Dim ser As Series
Dim tLine As Trendline
Dim cht As Chart, sNum As String
Set cht = ActiveSheet.ChartObjects(1).Chart
Set ser = cht.SeriesCollection(1)
If ser.Trendlines.Count = 1 Then
Set tLine = ser.Trendlines(1)
tLine.DisplayEquation = True
If tLine.DisplayEquation Then
sNum = tLine.DataLabel.NumberFormat
tLine.DataLabel.NumberFormat = "0.00000000000000E+00"
sFormula = tLine.DataLabel.Text
tLine.DataLabel.NumberFormat = sNum
sFormula = Application.Substitute(sFormula, _
"y = ", "")
sFormula = Application.Substitute(sFormula, _
"x", "*" & ActiveCell.Offset(0, -1).Address(0, 0) & "^")
sFormula = Application.Substitute(sFormula, _
"^ ", " ")
ActiveCell.Formula = "=" & sFormula
End If
End If
End Sub

In xl2K+ can use Replace iso Application.Substitute

In a long discussion last year it became clear that the formula is useless
without a high degree of precision.

Regards,
Peter T


<[email protected]> wrote in message
news:[email protected]...
> Hi,
>
> Based on a set of data, I've created a line pivot chart in Excel. I
> have added a trendline, wich works perfectly! So, why this question?
>
> Is it possible to get the specific values of a certain point on the
> trendline? For example:
>
>
> Pivot table:
>
> [AverageUse]
> Month Percentage
> 1 10,1234%
> 2 12,4678%
> 3 9,4373%
>
> Now I've create a pivot chart (that's a bit difficult to reproduce with
> ASCII-art and added a trendline, now I would like to see my pivot
> table like this:
>
> [AverageUse]
> Month Percentage TrendlinePercentage
> 1 10,1234% 9%
> 2 12,4678% 13%
> 3 9,4373% 9%
>
>
> Wich excel-guru has some briliant ideas?
>
> Thanks in advance,
>
> Best Regards,
>
> Alain
>

[Peter T]

I forgot to also to say this parses a third order polynomial, would need to
adapt for other formulas.

Regards,
Peter T

"Peter T" <peter_t@discussions> wrote in message
news:O#[email protected]...
> Look into Linest or better still various post by David Braden on the
> subject.
>
> If you particularly want to replicate your own trendline's formula you
could
> try something like this - parses the formula of trendline(1) in series 1
to
> a cell formula.
>
> start by selecting a cell offset one to right of the first value you want
to
> calculate
>
> Sub GetFormula1()
> Dim sFormula As String
> Dim ser As Series
> Dim tLine As Trendline
> Dim cht As Chart, sNum As String
> Set cht = ActiveSheet.ChartObjects(1).Chart
> Set ser = cht.SeriesCollection(1)
> If ser.Trendlines.Count = 1 Then
> Set tLine = ser.Trendlines(1)
> tLine.DisplayEquation = True
> If tLine.DisplayEquation Then
> sNum = tLine.DataLabel.NumberFormat
> tLine.DataLabel.NumberFormat = "0.00000000000000E+00"
> sFormula = tLine.DataLabel.Text
> tLine.DataLabel.NumberFormat = sNum
> sFormula = Application.Substitute(sFormula, _
> "y = ", "")
> sFormula = Application.Substitute(sFormula, _
> "x", "*" & ActiveCell.Offset(0, -1).Address(0, 0) & "^")
> sFormula = Application.Substitute(sFormula, _
> "^ ", " ")
> ActiveCell.Formula = "=" & sFormula
> End If
> End If
> End Sub
>
> In xl2K+ can use Replace iso Application.Substitute
>
> In a long discussion last year it became clear that the formula is useless
> without a high degree of precision.
>
> Regards,
> Peter T
>
>
> <[email protected]> wrote in message
> news:[email protected]...
> > Hi,
> >
> > Based on a set of data, I've created a line pivot chart in Excel. I
> > have added a trendline, wich works perfectly! So, why this question?
> >
> > Is it possible to get the specific values of a certain point on the
> > trendline? For example:
> >
> >
> > Pivot table:
> >
> > [AverageUse]
> > Month Percentage
> > 1 10,1234%
> > 2 12,4678%
> > 3 9,4373%
> >
> > Now I've create a pivot chart (that's a bit difficult to reproduce with
> > ASCII-art and added a trendline, now I would like to see my pivot
> > table like this:
> >
> > [AverageUse]
> > Month Percentage TrendlinePercentage
> > 1 10,1234% 9%
> > 2 12,4678% 13%
> > 3 9,4373% 9%
> >
> >
> > Wich excel-guru has some briliant ideas?
> >
> > Thanks in advance,
> >
> > Best Regards,
> >
> > Alain
> >
>
>

[Peter T]

I forgot to also to say this parses a third order polynomial, would need to
adapt for other formulas.

Regards,
Peter T

"Peter T" <peter_t@discussions> wrote in message
news:O#[email protected]...
> Look into Linest or better still various post by David Braden on the
> subject.
>
> If you particularly want to replicate your own trendline's formula you
could
> try something like this - parses the formula of trendline(1) in series 1
to
> a cell formula.
>
> start by selecting a cell offset one to right of the first value you want
to
> calculate
>
> Sub GetFormula1()
> Dim sFormula As String
> Dim ser As Series
> Dim tLine As Trendline
> Dim cht As Chart, sNum As String
> Set cht = ActiveSheet.ChartObjects(1).Chart
> Set ser = cht.SeriesCollection(1)
> If ser.Trendlines.Count = 1 Then
> Set tLine = ser.Trendlines(1)
> tLine.DisplayEquation = True
> If tLine.DisplayEquation Then
> sNum = tLine.DataLabel.NumberFormat
> tLine.DataLabel.NumberFormat = "0.00000000000000E+00"
> sFormula = tLine.DataLabel.Text
> tLine.DataLabel.NumberFormat = sNum
> sFormula = Application.Substitute(sFormula, _
> "y = ", "")
> sFormula = Application.Substitute(sFormula, _
> "x", "*" & ActiveCell.Offset(0, -1).Address(0, 0) & "^")
> sFormula = Application.Substitute(sFormula, _
> "^ ", " ")
> ActiveCell.Formula = "=" & sFormula
> End If
> End If
> End Sub
>
> In xl2K+ can use Replace iso Application.Substitute
>
> In a long discussion last year it became clear that the formula is useless
> without a high degree of precision.
>
> Regards,
> Peter T
>
>
> <[email protected]> wrote in message
> news:[email protected]...
> > Hi,
> >
> > Based on a set of data, I've created a line pivot chart in Excel. I
> > have added a trendline, wich works perfectly! So, why this question?
> >
> > Is it possible to get the specific values of a certain point on the
> > trendline? For example:
> >
> >
> > Pivot table:
> >
> > [AverageUse]
> > Month Percentage
> > 1 10,1234%
> > 2 12,4678%
> > 3 9,4373%
> >
> > Now I've create a pivot chart (that's a bit difficult to reproduce with
> > ASCII-art and added a trendline, now I would like to see my pivot
> > table like this:
> >
> > [AverageUse]
> > Month Percentage TrendlinePercentage
> > 1 10,1234% 9%
> > 2 12,4678% 13%
> > 3 9,4373% 9%
> >
> >
> > Wich excel-guru has some briliant ideas?
> >
> > Thanks in advance,
> >
> > Best Regards,
> >
> > Alain
> >
>
>

[Peter T]

I forgot to also to say this parses a third order polynomial, would need to
adapt for other formulas.

Regards,
Peter T

"Peter T" <peter_t@discussions> wrote in message
news:O#[email protected]...
> Look into Linest or better still various post by David Braden on the
> subject.
>
> If you particularly want to replicate your own trendline's formula you
could
> try something like this - parses the formula of trendline(1) in series 1
to
> a cell formula.
>
> start by selecting a cell offset one to right of the first value you want
to
> calculate
>
> Sub GetFormula1()
> Dim sFormula As String
> Dim ser As Series
> Dim tLine As Trendline
> Dim cht As Chart, sNum As String
> Set cht = ActiveSheet.ChartObjects(1).Chart
> Set ser = cht.SeriesCollection(1)
> If ser.Trendlines.Count = 1 Then
> Set tLine = ser.Trendlines(1)
> tLine.DisplayEquation = True
> If tLine.DisplayEquation Then
> sNum = tLine.DataLabel.NumberFormat
> tLine.DataLabel.NumberFormat = "0.00000000000000E+00"
> sFormula = tLine.DataLabel.Text
> tLine.DataLabel.NumberFormat = sNum
> sFormula = Application.Substitute(sFormula, _
> "y = ", "")
> sFormula = Application.Substitute(sFormula, _
> "x", "*" & ActiveCell.Offset(0, -1).Address(0, 0) & "^")
> sFormula = Application.Substitute(sFormula, _
> "^ ", " ")
> ActiveCell.Formula = "=" & sFormula
> End If
> End If
> End Sub
>
> In xl2K+ can use Replace iso Application.Substitute
>
> In a long discussion last year it became clear that the formula is useless
> without a high degree of precision.
>
> Regards,
> Peter T
>
>
> <[email protected]> wrote in message
> news:[email protected]...
> > Hi,
> >
> > Based on a set of data, I've created a line pivot chart in Excel. I
> > have added a trendline, wich works perfectly! So, why this question?
> >
> > Is it possible to get the specific values of a certain point on the
> > trendline? For example:
> >
> >
> > Pivot table:
> >
> > [AverageUse]
> > Month Percentage
> > 1 10,1234%
> > 2 12,4678%
> > 3 9,4373%
> >
> > Now I've create a pivot chart (that's a bit difficult to reproduce with
> > ASCII-art and added a trendline, now I would like to see my pivot
> > table like this:
> >
> > [AverageUse]
> > Month Percentage TrendlinePercentage
> > 1 10,1234% 9%
> > 2 12,4678% 13%
> > 3 9,4373% 9%
> >
> >
> > Wich excel-guru has some briliant ideas?
> >
> > Thanks in advance,
> >
> > Best Regards,
> >
> > Alain
> >
>
>

[Jerry W. Lewis]

Tushar Mehta has enhanced code by David Braden to extract coefficients
directly from a chart trendline
http://groups.google.com/group/micro...harting/msg/0e...
Note that for the chart trendline, you should format the equation to display
scientific notation with 14 decimal places.

Jerry

"K Dales" wrote:

> Unfortunately (as far as I know) Excel does not give you easy access to the
> trendline formula or its coefficients. You can, of course, calculate these
> yourself but since we know Excel has calculated them already (after all, you
> can choose to display the formula) it would be nice if the Trendline object
> had a .Formula property that could be used.
>
> But the best solution is to calculate them yourself from the chart's data
> series. For info on the formulas there is a handy reference here:
> http://j-walk.com/ss/excel/tips/tip101.htm
> --
> - K Dales
>
>
> "[email protected]" wrote:
>
> > Hi,
> >
> > Based on a set of data, I've created a line pivot chart in Excel. I
> > have added a trendline, wich works perfectly! So, why this question?
> >
> > Is it possible to get the specific values of a certain point on the
> > trendline? For example:
> >
> >
> > Pivot table:
> >
> > [AverageUse]
> > Month Percentage
> > 1 10,1234%
> > 2 12,4678%
> > 3 9,4373%
> >
> > Now I've create a pivot chart (that's a bit difficult to reproduce with
> > ASCII-art and added a trendline, now I would like to see my pivot
> > table like this:
> >
> > [AverageUse]
> > Month Percentage TrendlinePercentage
> > 1 10,1234% 9%
> > 2 12,4678% 13%
> > 3 9,4373% 9%
> >
> >
> > Wich excel-guru has some briliant ideas?
> >
> > Thanks in advance,
> >
> > Best Regards,
> >
> > Alain
> >
> >

[Peter T]

Sorry about the triple post. OE, first time a TCP error, sent once again, 3
in total!

Peter T

"Peter T" <peter_t@discussions> wrote in message
news:uRyF#[email protected]...
> I forgot to also to say this parses a third order polynomial, would need
to
> adapt for other formulas.
>