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Referring to an array column or row of LinEst function

  1. #1
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    Referring to an array column or row of LinEst function

    Hi,

    I am trying to use the LinEst function in a program. There are some good examples on the web but they all refer to a range in the format A1:A45. Is there a way to refer to a column in an existing array instead?

    For example (thanks to Shg for this code):

    Instead of:
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    Could I have

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    Where Array1 holds some data of interest.

    Hope this makes sense.
    Last edited by HammerTime; 01-13-2010 at 11:45 PM.

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    Re: Referring to an array column or row of LinEst function

    Hi

    Not sure I understood correctly.

    You mean like this?

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    Post Re: Referring to an array column or row of LinEst function

    Thanks that help, but I was thinking something like this:

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    Or is this not possible?

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    Re: Referring to an array column or row of LinEst function

    If it's an array, try:

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    Re: Referring to an array column or row of LinEst function

    You could do it like this:
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    Entia non sunt multiplicanda sine necessitate

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    Re: Referring to an array column or row of LinEst function

    Thanks to both of you, that is exactly what I'm after.

    Shg, what does the .Transpose do? This seems to be the main difference between your solution and lecxe's.

  7. #7
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    Re: Referring to an array column or row of LinEst function

    A single transpose converts a 2D column array to a 1D array.

    You should look in the Locals window as you step through the code with and without the transpose.

    Nothing will improve your coding like learning to debug.

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    Re: Referring to an array column or row of LinEst function

    Thanks for the tip

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