Hi,
https://ege.sdamgia.ru/test?pid=509161
sorry, in russian, but math is the only language we have
data: AC=12, CB=5, OC=0.5 (radius), so CB=13 and cosCAB=12/13
need to find NQ (radius).
solution - 2.
But it cannot be so
because for incircle radius according to r=(a+b-c)/2 we have 2 for ABC.
and possible triangle for our incircle (center in Q) is smaller. And radius must smaller then 2.
Isn't it?
BTW, I cannot find a strict way to draw it
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