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Dear experts,
kindly help, for solving the problem,
Counting no of stoppage frequencies in excel sheet.
kindly check the attachment.
regards.
Dear experts,
kindly help, for solving the problem,
Counting no of stoppage frequencies in excel sheet.
kindly check the attachment.
regards.
Your request is not clear. You need to tell us what results you expect and how you manually calculate them.
Richard Buttrey
RIP - d. 06/10/2022
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I want to know that,
how many time my equipment stopped within the dates,
In attached file, equipment stopped 8 time, i want the formula,
thanks.
And how have you arrived at the value of 8?
Ali
Enthusiastic self-taught user of MS Excel who's always learning!
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Kindly check the attached file.
regards.
Please could you explain in words in your next post the logic behind your calculations and the significance of the cells highlighted in yellow? I am afraid it is still far from clear, to me, at least.
Dear AliGW
In yellow colour, Equipment stopped on 03/06/2016 at 13:30 hours and started next day 04/06/2016 at 13:20 (cell no. B6 and B7).
on 03/06/2016 stopped for 10.50 hours
on 04/06/2016 stopped for 13:20 hours
this will count 1 stoppage because it was stopped continously 2 days (03/06/2016 to 04/06/2016).
if it break the date or time, it will count 2 stoppages as shown in "Cell no. B4 and B5.
Thanks
Hi,
You appear to be counting C13:D15 as one stoppage, however there is a gap between D14 & C15 so surely there are two stoppages and in total 9 rather than 8.
Please clarify.
Yes, Richard you are right, total 9 stoppages, not 8.
regards,
May be this ?
=SUMPRODUCT(--(B$4:B$15<>C$3:C$14))
Dear Soledad / Experts
Kindly apply this formula in the latest attached file.
regards,
This in E4 copied down (you will need to un-merge those cells first, though):
=SUMPRODUCT(--(B$4:B4<>C$3:C3))
Or this
=IF(B4<>C3,SUMPRODUCT(--(B$4:B4<>C$3:C3)),"")
Solved the problem.
Thank you very much, all expert specially AliGW and Soledad.
regards.
You're welcome, but it was Soledad's solution: all I did was tweak it to make it incremental.
Thanks to all friends.
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