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counting in 2003 - sorry if this is an easy one!

  1. #1
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    counting in 2003 - sorry if this is an easy one!

    Hi all,

    To me, this seems to be an ultra-easy question, but I can't find a workable solution through Google.
    I have two columns with data, something like this:
    | customer | Y |
    | vendor | N |
    | customer | N |
    | customer | Y |
    I just want to count how many of each combination I have. So I have a separate table with how many customer Y, how many customer N, etc. etc.

    I seem to find this ought to be COUNTIFS(A:A, "customer", B:B, "Y") to find how many Customer Y. But I'm using Excel 2003. I've also found some suggesting SUMPRODUCT, but it just doesn't seem to work for me.

    Please help!
    Thanks.

  2. #2
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    Re: counting in 2003 - sorry if this is an easy one!

    Hi

    maybe SUMPRODUCT, but reducing the ranges read by formula (not A:A B:B)


    =SUMPRODUCT((A$1:A$1000="customer")*(B$1:B$1000="Y"))

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    Re: counting in 2003 - sorry if this is an easy one!

    that is currently working. I need to add a bit more data to test it, but THANK YOU!!!

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    Re: counting in 2003 - sorry if this is an easy one!

    Countifs is faster compared to Sumproduct
    Pl note
    Array formula should be confirmed with Ctrl+Shift+Enter keys together.
    If answere is satisfactory press * to add reputation.

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    Re: counting in 2003 - sorry if this is an easy one!

    Your data in a & b column
    In "C2" use
    Formula: copy to clipboard
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    copy paste down till end of record.
    Formula: copy to clipboard
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    confirm by pressing CTRL+SHIFT+ENTER


    atul


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