I had modified the ranges to match some sample data I typed in when I tried
to disect the formulas.
I've really learned a lot by studying the replies on these newsgroups.
Thank you very much for your time.
Lewis
"Bob Phillips" <[email protected]> wrote in message
news:%[email protected]...
> The find will return an array of values depending upon whether it finds
> the
> value or not, 1 for matches, #VALUE for non-matches (BTW you need to
> reduce
> the range size if you want to evaluate the formula). It provides
> case-sensitiveness by virtue of the FIND function.
>
> The array of values is then used to LOOKUP the BigNumber in the
> lookup_vector. LOOKUP returns an index to the largest number less than the
> lookup value, and uses that to extract from the result_vector Z2:Z3000. As
> the array only consists of 1 and #VALUE, the largest values less than or
> euqla will be 1. That has made me just realise, you don't need BigNumber,
> 2
> will do
>
> =LOOKUP(2,FIND(AA1,A2:A3000),Z2:Z3000)
>
> Much more economical :-)
>
> This actually works slightly differently than my offering, as if there are
> multiple matches in the lookup_vector, this formula returns the last, mine
> returns the first.
>
> --
>
> HTH
>
> RP
> (remove nothere from the email address if mailing direct)
>
>
> "Lewis Clark" <lewis_clark_644 @ yahoo.com> wrote in message
> news:4oHMe.7333$Al5.5850@trnddc04...
>> Would you please explain the logic for this formula? I think I
>> understand
>> what it does, but not how it works.
>>
>> It looks like FIND returns the position in the "A" range of the lookup
>> value, and then LOOKUP returns the corresponding value from the "Z"
>> range.
>>
>> When I try to break out the FIND call by itself to follow the logic, I
> just
>> get the #VALUE! error. Does FIND return a vector in this case that is
>> all
>> zeros except for the position of the lookup value?
>>
>> Thanks in advance.
>>
>>
>> "Krishnakumar"
>> <[email protected]>
>> wrote in message
>> news:[email protected]...
>> >
>> > Hi Dan,
>> >
>> > May be...
>> >
>> > =LOOKUP(9.9999999999E+307,FIND(AA1,A2:A3000),Z2:Z3000)
>> >
>> > where AA1 houses the lookup value.
>>
>>
>
>
Bookmarks