difficult array formula

I have to formulas:

1) 1 = C/252*days(1)*d(1) + c/252*days(2)*d(2) + c/252*days(3)*d(3) +
d3

and

2) 1 = (1+C)^(days(1)/252)*d(1) + (1+C)^(days(2)1/252)*d(2) +
(1+C)^(days(3)/252)*d(3) + d(3)

days and d are ranges representing days and discount factors
respectively.

I would like to solve for C, the coupon that is paid in each period.

Formula 1 is easy:

=252*(1-B3)/sum(A1:A3*B1:B3)

where range B1:B3 is the d() array and A1:A3 is the days() array.

Now a formula for equation 2..........

If my algebra is correct...

C = ((1-d(3))^(252/(d(1)days(1))+(d(2)days(2))+(d(3)days(3))))-1

HTH,
--
Gary Brown
gary_brown@ge_NOSPAM.com
If this post was helpful, please click the ''Yes'' button next to ''Was this
Post Helpfull to you?''.


"Shaz" wrote:

> I have to formulas:
>
> 1) 1 = C/252*days(1)*d(1) + c/252*days(2)*d(2) + c/252*days(3)*d(3) +
> d3
>
> and
>
> 2) 1 = (1+C)^(days(1)/252)*d(1) + (1+C)^(days(2)1/252)*d(2) +
> (1+C)^(days(3)/252)*d(3) + d(3)
>
> days and d are ranges representing days and discount factors
> respectively.
>
> I would like to solve for C, the coupon that is paid in each period.
>
> Formula 1 is easy:
>
> =252*(1-B3)/sum(A1:A3*B1:B3)
>
> where range B1:B3 is the d() array and A1:A3 is the days() array.
>
> Now a formula for equation 2..........
>
>