How to use HLOOKUP or other command to find a value within a range

Simple question...I am looking for a value within a range of nine cells in a
row. If the value is not present I would like for the value that is not
present (false) to be displayed. I tried a nested if statement, but the will
only work on 7 conditions.

For example: Take your average Suduko game. In Row1, numbers 1-9 can
appear in a random order. If I want to know if the number 1 has been entered
in any of the nine row cells, logically I would say "If the contents within
B2:B10<>1, display 1" and repeat in the next cell, "If the contents within
B2:B10<>2,display 2" and so on...up to the number 9. This way the person
doing the puzzle will know what entries are left.

B2 B3 B4 B5 B6 B7 B8 B9 B10 B11 B15 MISSING
VALUE
Row1 6 7 9 2 1 5
=formula to check for value

If not present, value is

displays

Corrected Example...

B2 B3 B4 B5 B6 B7 B8 B9 B10 B15 MISSING VALUE
Row1 6 7 9 2 1 5 =formula to
check for value
If
not present, value displays

What do you want to return if the value is present? Nothing?

=IF(COUNTIF($B$2:$B$10,ROWS($B$1:B1))=0,ROWS($B$1:B1),"")

copy down

btw one of the MS Excel developers (Dan Cory) has constructed a Sudoko
solver using built in functions

http://office.microsoft.com/en-us/te...809721033.aspx

another one using code is here (by MVP Andy Pope)

http://andypope.info/fun/sudoku.htm



--
Regards,

Peo Sjoblom

(No private emails please)


"antwash" <[email protected]> wrote in message
news:[email protected]...
> Simple question...I am looking for a value within a range of nine cells in
> a
> row. If the value is not present I would like for the value that is not
> present (false) to be displayed. I tried a nested if statement, but the
> will
> only work on 7 conditions.
>
> For example: Take your average Suduko game. In Row1, numbers 1-9 can
> appear in a random order. If I want to know if the number 1 has been
> entered
> in any of the nine row cells, logically I would say "If the contents
> within
> B2:B10<>1, display 1" and repeat in the next cell, "If the contents within
> B2:B10<>2,display 2" and so on...up to the number 9. This way the person
> doing the puzzle will know what entries are left.
>
> B2 B3 B4 B5 B6 B7 B8 B9 B10 B11 B15 MISSING
> VALUE
> Row1 6 7 9 2 1 5
> =formula to check for value
>
> If not present, value is
>
> displays

Thanks much Peo Sjoblom... That did the trick. The links were good too..
they helped me better understand the function..

"Peo Sjoblom" wrote:

> What do you want to return if the value is present? Nothing?
>
> =IF(COUNTIF($B$2:$B$10,ROWS($B$1:B1))=0,ROWS($B$1:B1),"")
>
> copy down
>
> btw one of the MS Excel developers (Dan Cory) has constructed a Sudoko
> solver using built in functions
>
> http://office.microsoft.com/en-us/te...809721033.aspx
>
> another one using code is here (by MVP Andy Pope)
>
> http://andypope.info/fun/sudoku.htm
>
>
>
> --
> Regards,
>
> Peo Sjoblom
>
> (No private emails please)
>
>
> "antwash" <[email protected]> wrote in message
> news:[email protected]...
> > Simple question...I am looking for a value within a range of nine cells in
> > a
> > row. If the value is not present I would like for the value that is not
> > present (false) to be displayed. I tried a nested if statement, but the
> > will
> > only work on 7 conditions.
> >
> > For example: Take your average Suduko game. In Row1, numbers 1-9 can
> > appear in a random order. If I want to know if the number 1 has been
> > entered
> > in any of the nine row cells, logically I would say "If the contents
> > within
> > B2:B10<>1, display 1" and repeat in the next cell, "If the contents within
> > B2:B10<>2,display 2" and so on...up to the number 9. This way the person
> > doing the puzzle will know what entries are left.
> >
> > B2 B3 B4 B5 B6 B7 B8 B9 B10 B11 B15 MISSING
> > VALUE
> > Row1 6 7 9 2 1 5
> > =formula to check for value
> >
> > If not present, value is
> >
> > displays
>
>

Based on your formula... I was able to figure it out...

i.e. searching for the number 1 in affected row, showing that it was used
and displaying the number if it is not used.

=IF(COUNTIF(B2:J2,1),"Used","1")

Thanks much for your assistance. This group rocks!

"Peo Sjoblom" wrote:

> What do you want to return if the value is present? Nothing?
>
> =IF(COUNTIF($B$2:$B$10,ROWS($B$1:B1))=0,ROWS($B$1:B1),"")
>
> copy down
>
> btw one of the MS Excel developers (Dan Cory) has constructed a Sudoko
> solver using built in functions
>
> http://office.microsoft.com/en-us/te...809721033.aspx
>
> another one using code is here (by MVP Andy Pope)
>
> http://andypope.info/fun/sudoku.htm
>
>
>
> --
> Regards,
>
> Peo Sjoblom
>
> (No private emails please)
>
>
> "antwash" <[email protected]> wrote in message
> news:[email protected]...
> > Simple question...I am looking for a value within a range of nine cells in
> > a
> > row. If the value is not present I would like for the value that is not
> > present (false) to be displayed. I tried a nested if statement, but the
> > will
> > only work on 7 conditions.
> >
> > For example: Take your average Suduko game. In Row1, numbers 1-9 can
> > appear in a random order. If I want to know if the number 1 has been
> > entered
> > in any of the nine row cells, logically I would say "If the contents
> > within
> > B2:B10<>1, display 1" and repeat in the next cell, "If the contents within
> > B2:B10<>2,display 2" and so on...up to the number 9. This way the person
> > doing the puzzle will know what entries are left.
> >
> > B2 B3 B4 B5 B6 B7 B8 B9 B10 B11 B15 MISSING
> > VALUE
> > Row1 6 7 9 2 1 5
> > =formula to check for value
> >
> > If not present, value is
> >
> > displays
>
>