Filling in a number x, y times in y cells

This is a difficult one to explain, so I will provide an example:

a 1
b 2
c 3
d 10
e
f
g
h
i
j 2
k 5

Rows a through c contain a value for a given period, while row d contains a
lump sum for all future periods. Row j is the average of rows a through c
(which I am using as an estimate of future periodic values), while row k is
row d divided by the average calculated in row j (the number of periods
necessary until the lump sum is reached). What I am trying to do is then
repeat the average calculated in row j in rows e through i the number of
times shown in row k (thereby giving me 8 periodic values as opposed to 3
periodic values and one lump sum). Any ideas on how to do this?

Thanks so much for the help.

Not sure, but perhaps this plunge
might start the ball rolling here <g> ..

Assuming the example data is in A1:B11,
where you probably have
in B10: =AVERAGE(B1:B3)
in B11: =B4/B10
(I'm just reading it straight from your post)

Then, perhaps just put in B5: =$B$10,
and copy B5 down to B9

Is that it ?
--
Max
Singapore
http://savefile.com/projects/236895
xdemechanik
---
"Damien" <[email protected]> wrote in message
news:[email protected]...
> This is a difficult one to explain, so I will provide an example:
>
> a 1
> b 2
> c 3
> d 10
> e
> f
> g
> h
> i
> j 2
> k 5
>
> Rows a through c contain a value for a given period, while row d contains
a
> lump sum for all future periods. Row j is the average of rows a through c
> (which I am using as an estimate of future periodic values), while row k
is
> row d divided by the average calculated in row j (the number of periods
> necessary until the lump sum is reached). What I am trying to do is then
> repeat the average calculated in row j in rows e through i the number of
> times shown in row k (thereby giving me 8 periodic values as opposed to 3
> periodic values and one lump sum). Any ideas on how to do this?
>
> Thanks so much for the help.
>
>

That would do it in this case, but my problem is that I'm trying to automate
the process. I'm using a Bloomberg feed that would automatically fill in data
for five years and then one lump sum for all future years. Those values will
always be different, so I will always have a different average and number of
times that the average divides into the lump sum...

I suspect that there isn't a simple function to do this - perhaps I'll play
around with VBA and see if I can work something out.

Thanks for the response though. Take it easy.

"Max" wrote:

> Not sure, but perhaps this plunge
> might start the ball rolling here <g> ..
>
> Assuming the example data is in A1:B11,
> where you probably have
> in B10: =AVERAGE(B1:B3)
> in B11: =B4/B10
> (I'm just reading it straight from your post)
>
> Then, perhaps just put in B5: =$B$10,
> and copy B5 down to B9
>
> Is that it ?
> --
> Max
> Singapore
> http://savefile.com/projects/236895
> xdemechanik
> ---
> "Damien" <[email protected]> wrote in message
> news:[email protected]...
> > This is a difficult one to explain, so I will provide an example:
> >
> > a 1
> > b 2
> > c 3
> > d 10
> > e
> > f
> > g
> > h
> > i
> > j 2
> > k 5
> >
> > Rows a through c contain a value for a given period, while row d contains
> a
> > lump sum for all future periods. Row j is the average of rows a through c
> > (which I am using as an estimate of future periodic values), while row k
> is
> > row d divided by the average calculated in row j (the number of periods
> > necessary until the lump sum is reached). What I am trying to do is then
> > repeat the average calculated in row j in rows e through i the number of
> > times shown in row k (thereby giving me 8 periodic values as opposed to 3
> > periodic values and one lump sum). Any ideas on how to do this?
> >
> > Thanks so much for the help.
> >
> >
>
>
>

Thanks for the clarification !

> .. That would do it in this case,
> but my problem is that I'm trying to automate the process.

Yes, of course, that would be the usual inference <g>

Just to move it along a little further here ..

".. Bloomberg feed ..."
This may well be second nature to you,
but probably not to a lot of us

Perhaps you could either* paste some representative data of how the feed
actually appears in the sheet in plain text in your reply (showing some
variations). Tell us how we can "identify" which cell in the col will
contain the lump sum, how to identify when one feed ends and the other
begins, etc, etc (the variation patterns)

*Alternatively, upload a small sample file
and paste the *link* to it in your reply

Some free filehosts that could be used to upload your sample:
http://www.flypicture.com/
http://cjoint.com/index.php
http://www.savefile.com/index.php

For cjoint.com (it's in French), just click "Browse" button, navigate to
your folder > select the sample file > Open, then click the button centred
in the page below (labelled "Creer le lien Cjoint") and it'll
generate the link. Then copy & paste the generated link as part and parcel
of your response here.

Kindly note that no attachments
should be posted *directly* to the newsgroup

I'm not saying I'd ultimately have a further (formula) suggestion to offer
(it may be beyond me), but, if you deepen your clarification further here as
suggested above, it'll be visible to the many other regular responders out
there, some of whom may well have something to offer you.

Either way, kindly post a closure response here to let us know whether
you're keen to pursue this further. Cheers.
--
Max
Singapore
http://savefile.com/projects/236895
xdemechanik
---
"Damien" <[email protected]> wrote in message
news:[email protected]...
> That would do it in this case, but my problem is that I'm trying to
automate
> the process. I'm using a Bloomberg feed that would automatically fill in
data
> for five years and then one lump sum for all future years. Those values
will
> always be different, so I will always have a different average and number
of
> times that the average divides into the lump sum...
>
> I suspect that there isn't a simple function to do this - perhaps I'll
play
> around with VBA and see if I can work something out.
>
> Thanks for the response though. Take it easy.