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Games Behind Formula

  1. #1
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    Games Behind Formula

    I have tried to figure out the formula to calculate how many games behind a team is in a division. I tried the following but comes close to the right calculation but no cigar.


    TEam 1 20Wins 5 Losses ----
    Team 2 18 wins 7 Losses 2 GB Calculation comes up as 3.

    =(B5-B6)+(C6-C5)/2

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    1. How do you define "games behind"?
    2. You gave us a formula, but you don't specify what values are in which cell.
    Ben Van Johnson

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    try:

    =((b5-b6)+(c6-c5))/2

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    GAmes Behind Formula

    Wins Losses Pct Games Behind
    Team 1 20(cell B5) 5(cell C5 0800 ---------
    Team 2 18(CellB6) 7(Cell C6 0.720 2
    Team 3 18(CellB7) 8(cell c7) 0.692 2.5


    Subtract 20-18=2 and 7-5=2 2+2=4 /2 equals 2 Games Behind

    Subtract 20-18=2 and 8 -5=3, 3=2=5 /2 = 2.5 games behind
    Attached Files Attached Files

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    Quote Originally Posted by Milomet
    Wins Losses Pct Games Behind
    Team 1 20(cell B5) 5(cell C5 0800 ---------
    Team 2 18(CellB6) 7(Cell C6 0.720 2
    Team 3 18(CellB7) 8(cell c7) 0.692 2.5


    Subtract 20-18=2 and 7-5=2 2+2=4 /2 equals 2 Games Behind

    Subtract 20-18=2 and 8 -5=3, 3=2=5 /2 = 2.5 games behind
    A more formula based solution would be:

    =((max($b$5:$b$100)-b6)+(c6-(min($c$5:$c$100))/2

    This will subract the team with the most wins from the current team, the subtract the losses of the current team from the team with the fewest losses, then add those two number together and finally dividing by 2.

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    Games Behind Formula

    Thanks bSweetOus. It worked

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    Re: Games Behind Formula

    That formula works fine as long as there are no tie games involved. How do I modify the formula to account for ties?

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    Quote Originally Posted by Bau View Post
    That formula works fine as long as there are no tie games involved. How do I modify the formula to account for ties?
    Tie games are commonly considered half a win and half a loss. Assuming you are considering them the same, the following should work.

    =(((max($B$2:$B$100)+(D2/2))-B2)+((D2/2)+C2-min($C$2:$C$100)))/2

    This is assuming "wins" are in column B, "losses" in column C and "ties" in column D. The ranges for max and min would start at the uppermost cell that contains a win or loss and end with the bottom most cell that contains a value involving the items you're comparing.

    For example, if you have different divisions of four teams each and the wins and losses for the first division are located in cells B2:C5, your max and min ranges would be $B$2:$B$5 and $C$2:$C$5, respectively.

    Also note that teams that have completed a different number of games can skew the games behind computation and winning percentage is a better indicator of placement.

    Hope this helps!

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    Re: Games Behind Formula

    Bau,
    Administrative Note:

    Welcome to the forum.

    We are happy to help, however whilst you feel your request is similar to this thread, experience has shown that things soon get confusing when answers refer to particular cells/ranges/sheets which are unique to your post and not relevant to the original.

    Please see Forum Rule #4 about hijacking and start a new thread for your query.

    If you are not familiar with how to start a new thread see the FAQ: How to start a new thread

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