I'm wondering if someone could help me. I'm working on a formula to get the the path of a picture on a different sheet in a workbook. I am trying to get use the hyperlink function to reference that cell on the the other sheet. It looks right but I get an error saying that it cannot open the specified file. This is what my formula looks like:
=HYPERLINK(ADDRESS(4,12,2,,"Sheet 1"),2)
I need it to actually get the actual text value of the cell I am trying to reference. How would I do that?
Thanks.
Bookmarks