Sum digits in a cell plus the number digits-Ready for this

It's not complicated it just looks that way.
I am adding up each individual digit in a cell and then adding the number of digits to the sum of the individual digits. Read it twice if I lost you.
Step 1 in K6 - K12 put the following:
11,111,111.11 then
1,111,111.11 then
111,111.11 then
11,111.11
1,111.11
111.11
11.11
Here is the formula I have so far to handle through row K10:
=IF(LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))=10,SUM(LEFT(K6,1)+MID(K6,2,1)+MID(K6,3,1)+MID(K6,4,1)+MID(K6,5,1)+MID(K6,6,1)+MID(K6,7,1)+MID(K6,8,1)+MID(K6,10,1))+MID(K6,11,1),IF(LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))=9,SUM(LEFT(K6,1)+MID(K6,2,1)+MID(K6,3,1)+MID(K6,4,1)+MID(K6,5,1)+MID(K6,6,1)+MID(K6,7,1)+MID(K6,9,1)+MID(K6,10,1)),IF(LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))=8,SUM(LEFT(K6,1)+MID(K6,2,1)+MID(K6,3,1)+MID(K6,4,1)+MID(K6,5,1)+MID(K6,6,1)+MID(K6,8,1)+MID(K6,9,1)),IF(LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))=7,SUM(LEFT(K6,1)+MID(K6,2,1)+MID(K6,3,1)+MID(K6,4,1)+MID(K6,5,1)+MID(K6,7,1)+MID(K6,8,1)),IF(LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))=6,SUM(LEFT(K6,1)+MID(K6,2,1)+MID(K6,3,1)+MID(K6,4,1)+MID(K6,6,1)+MID(K6,7,1)),"'TRY AGAIN")))))+LEN(TEXT(--SUBSTITUTE(ROUND(K6,2)&"",".",""),"0#"))
The problem is once I get to the formula for K10 it no longer works?
Any ideas why it won't work for K10, K11, and K12

Sorry I forgot the resulting answers should be 20, 18, 16, 14, 12, 10, 8

I'd like to see a more representative sample of data, presumably they won't always be 1s. Will they always have at most 2 decimal places?

For your example perhaps you could use this version, quite similar to Ron's suggestion

=LEN(A1*100)+SUMPRODUCT(MID(A1*100,ROW(INDIRECT("1:"&LEN(A1*100))),1)+0)

Wow...Both examples are so much simpler than mine. Both formulas work, The sample of data even though it is just one's will always provide the same result. It could be any number really, the point being that it sums the digits and then adds the number (len) of digits to the sum. I have been working on this for a while and finally brought it to this forum. I think some solutions are best tried and failed several times before putting it out to this forum.
Thanks