Finding the first item in a subset

Hello
I have been trying to find an answer to this question almost the whole day.. Please help!
I have a list that kind of looks like this. I sorted it by date, then by location, and then by time. I need to find the earliest item in one location on a given day and display as a list. Any ideas? Thanks!

date location time
6/1/2013 A 730
6/1/2013 A 745
6/1/2013 A 750
6/1/2013 B 800
6/1/2013 B 810
6/1/2013 C 730
6/1/2013 C 745
6/1/2013 C 800
6/1/2013 C 815
6/2/2013 A 730
6/2/2013 A 745
6/2/2013 A 800
6/2/2013 A 815
6/2/2013 B 700
6/2/2013 B 800
6/2/2013 B 815
6/2/2013 C 800
6/2/2013 C 815

Ok. This is what I want to see (in bold). I need the first item in each location on a given day, since it is already sorted out by value. Thanks!

6/1/2013 A 730
6/1/2013 A 745
6/1/2013 A 750
6/1/2013 B 800
6/1/2013 B 810
6/1/2013 C 730
6/1/2013 C 745
6/1/2013 C 800
6/1/2013 C 815
6/2/2013 A 730
6/2/2013 A 745
6/2/2013 A 800
6/2/2013 A 815
6/2/2013 B 700
6/2/2013 B 800
6/2/2013 B 815
6/2/2013 C 800
6/2/2013 C 815

I would rather see them as a list in a different location so I can do further work.

In the attached file I've shown in stages how you can use formulae to achieve this. Combine A and B in column E, extract the unique values in column G, then split the date and location out in I & J, and finally return the value of the first occurrence in column K.

Hope this helps.

Pete

ie range data at A2:C19

start filter formula at E2 (array formula)
{=IFERROR(INDEX(A$2:A$19,SMALL(IF(MATCH($A$2:$A$19&$B$2:$B$19,$A$2:$A$19&$B$2:$B$19,0)=ROW($A$2:$A$19)-1,MATCH($A$2:$A$19&$B$2:$B$19,$A$2:$A$19&$B$2:$B$19,0)),ROW(1:1))),"")}

drag right and down

(see attachment)

You guys are awesome! Thanks a lot!