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remove duplicate value within a row but keep first found value and remove the rest

  1. #1
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    remove duplicate value within a row but keep first found value and remove the rest

    Hi MVPs

    i currently working on a list which contains several data horizontally, it contain some duplicate value within a row. i want to remove all duplicate but keep first found value and not delete entire row. since it's over 9000 rows, it would be painfull to do it manually

    please your kind help and attached file for you to have clarity about what my problem is

    thank you very much for your help

  2. #2
    Forum Guru TMS's Avatar
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    Are you still using Excel 2010?

    With 365 you can use:
    Formula: copy to clipboard
    Please Login or Register  to view this content.
    Trevor Shuttleworth - Retired Excel/VBA Consultant

    I dream of a better world where chickens can cross the road without having their motives questioned

    'Being unapologetic means never having to say you're sorry' John Cooper Clarke


  3. #3
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    i forgot to change excel version in my profile, no currently i'm using 2016 version

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    Forum Moderator Glenn Kennedy's Avatar
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    For Excel 2016:

    =IFERROR(INDEX(2:2,AGGREGATE(15,6,COLUMN($B2:$Q2)/(($B2:$Q2<>"")*(COUNTIF($A7:A7,$B2:$Q2)=0)),1)),"")

    copied across and down.
    Glenn




    None of us get paid for helping you... we do this for fun. So DON'T FORGET to say "Thank You" to all who have freely given some of their time to help YOU

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    Re: remove duplicate value within a row but keep first found value and remove the rest

    vba
    try
    Please Login or Register  to view this content.

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    Re: remove duplicate value within a row but keep first found value and remove the rest

    Glenn Kennedy & jindon

    please accept the star to both of you, both solution is exactly what i need. this thread is SOLVED

    thank you so much

  7. #7
    Forum Expert bebo021999's Avatar
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    Another option
    Assuming your source sheet is Sheet1, the result will be in Sheet2.

    PHP Code: 
    Option Explicit
    Sub dup
    ()
    Dim lr&, i&, j&, k&, rngdic As Objectspsres(), As Boolean
    With Sheets
    ("Sheet1")
        
    lr = .Cells(Rows.Count"A").End(xlUp).Row ' last used row of col A
        rng = .Range("A2:M" & lr).Value ' 
    expand range into actual range
        ReDim res
    (1 To UBound(rng), 1 To UBound(rng2))
    End With
    For 1 To UBound(rng)
        
    Set dic CreateObject("Scripting.Dictionary")
        
    0
        
    For 1 To UBound(rng2)
            If 
    Not IsEmpty(rng(ij)) Then
                c 
    Falsesp Split(rng(ij), ",")
                For 
    Each s In sp
                    
    If Not dic.exists(sThen
                        dic
    .Add s""
                        
    True
                    End 
    If
                
    Next
                
    If c Then k 1res(ik) = rng(ij)
            
    End If
        
    Next
    Next
    Sheets
    ("sheet2").Activate
    Range
    ("A2:XX100000").ClearContents
    Range
    ("A2").Resize(UBound(res), UBound(res2)).Value res
    End Sub 
    Quang PT

  8. #8
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    Quote Originally Posted by TMS View Post
    Are you still using Excel 2010?

    With 365 you can use:
    Formula: copy to clipboard
    Please Login or Register  to view this content.
    tested to my personal laptop which using 365 and worked as well, even currently i'm working at company that still using 2016, please accept the star for you

  9. #9
    Forum Guru TMS's Avatar
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    Re: remove duplicate value within a row but keep first found value and remove the rest

    You're welcome. Thanks for the rep.

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