If then statement causing value issues in Macros

I have three sheets in my workbook for journal upload form.

Sheet Ldr Jrnl Entry is the users journal data input
Sheet GL Upload is the Financial ERP system upload file
Sheet Actions is the macro buttons to fire off the VB macros

For GL Upload Sheet there is an accrual field and when this is blank it must
be removed before uploading.

I created this simple VB statement

Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft

The problem is that if the users have an accrual I do not want to have them
delete this field.

So I thought if the field is 1/01/1900 then do this:

If Sheets("GL Upload").Columns("T:T").Value = "01/01/1900" Then
Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft
End If

My problem is that Column T references Sheet Ldr Jrnl Entry. If you click
any row on Column T you see this ='Ldr Jrnl Entry'!AT12 and not 01/01/1900.
01/01/1900 only shows because of cell formatting.

I keep getting a type mismatch error when running the If then macro..

I am novice at best at VB and needs to guidance to how to 'trick' the
referenced cell to be some type of value...

Hi,
what about comparing with the Text property of the cell instead of the Value
property?
If Sheets("GL Upload").Columns("T:T").Text = "01/01/1900"

--
Regards,
Sébastien
<http://www.ondemandanalysis.com>


"ssciarrino" wrote:

> I have three sheets in my workbook for journal upload form.
>
> Sheet Ldr Jrnl Entry is the users journal data input
> Sheet GL Upload is the Financial ERP system upload file
> Sheet Actions is the macro buttons to fire off the VB macros
>
> For GL Upload Sheet there is an accrual field and when this is blank it must
> be removed before uploading.
>
> I created this simple VB statement
>
> Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft
>
> The problem is that if the users have an accrual I do not want to have them
> delete this field.
>
> So I thought if the field is 1/01/1900 then do this:
>
> If Sheets("GL Upload").Columns("T:T").Value = "01/01/1900" Then
> Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft
> End If
>
> My problem is that Column T references Sheet Ldr Jrnl Entry. If you click
> any row on Column T you see this ='Ldr Jrnl Entry'!AT12 and not 01/01/1900.
> 01/01/1900 only shows because of cell formatting.
>
> I keep getting a type mismatch error when running the If then macro..
>
> I am novice at best at VB and needs to guidance to how to 'trick' the
> referenced cell to be some type of value...
>
>
>
>
>

Sebastienm,

Thanks for the heads up...well the good news...it didn't bomb with an error
but running it does nothing..the column still exists...

is there another value besides text, i.e. cell format or something that
could achieve what I am looking for?

"sebastienm" wrote:

> Hi,
> what about comparing with the Text property of the cell instead of the Value
> property?
> If Sheets("GL Upload").Columns("T:T").Text = "01/01/1900"
>
> --
> Regards,
> Sébastien
> <http://www.ondemandanalysis.com>
>
>
> "ssciarrino" wrote:
>
> > I have three sheets in my workbook for journal upload form.
> >
> > Sheet Ldr Jrnl Entry is the users journal data input
> > Sheet GL Upload is the Financial ERP system upload file
> > Sheet Actions is the macro buttons to fire off the VB macros
> >
> > For GL Upload Sheet there is an accrual field and when this is blank it must
> > be removed before uploading.
> >
> > I created this simple VB statement
> >
> > Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft
> >
> > The problem is that if the users have an accrual I do not want to have them
> > delete this field.
> >
> > So I thought if the field is 1/01/1900 then do this:
> >
> > If Sheets("GL Upload").Columns("T:T").Value = "01/01/1900" Then
> > Sheets("GL Upload").Columns("T:T").Delete Shift:=xlToLeft
> > End If
> >
> > My problem is that Column T references Sheet Ldr Jrnl Entry. If you click
> > any row on Column T you see this ='Ldr Jrnl Entry'!AT12 and not 01/01/1900.
> > 01/01/1900 only shows because of cell formatting.
> >
> > I keep getting a type mismatch error when running the If then macro..
> >
> > I am novice at best at VB and needs to guidance to how to 'trick' the
> > referenced cell to be some type of value...
> >
> >
> >
> >
> >