In this instance, the intuitive answer is the
correct one. In particular, the probability
that 5 is included in your set of four numbers
given that 6 is included is 3/9 = 1/3.
This can be verified by the calculation
(8 choose 2)/(9 choose 3).
The numerator being the number of ways to select
two numbers from eight (the 5 and 6 being
prescribed) and the denominator being the
number of ways to select three numbers from nine
(the 6 being prescribed). I hope this is
helpful to you. Often the unintuitive solution
is the correct one, but not in this case.
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