Hi. I need a vba code to open a subfolder thats is created where the .xlsm file is being executed. I have a file called Menu.xlsm inside a folder called RESTAURANT(in desktop). Inside this folder i have Menu file (which i'm running) and a subfolder called EXTRACT. I want a peace of code that runs on Menu file to open EXTRACT. The thing is that Menu file may not allways be inside RESTAURANT folder or this folder may not allways be located in desktop. The constant is the subfolder EXTRACT which is allways inside a folder located somewhere with Menu.xlsm in the same folder as EXTRACT. Basicaly i need it to open EXTRACT independent where it is located. If ecel cannot find it inside the folder where Menu.xlsm is i´ll handle it Herror Handler.
The same way i need a code to open a print.xlsm file that is located in the same folder as Menu.xlsm file. This one is another macro to be assigned to other button. But i guess it uses the same parameters as the first one.
Hope someone could help with this
Thank you
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