Trim trailing CR/LF character(s) off of string variable

Hello!

I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.

Is there an easy way to do something similar to the following that will remove the CR/LF characters?

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Thank you

Thank you 6StringJazzer! Worked like a champ.

Ciao!

You're welcome! Thanks for the rep, and thanks for marking your thread Solved!

Sorry to Unsolve this! After doing some testing, I noticed that the code suggested by the ever-helpful 6StringJazzer removes ALL CR and/or LF characters from my string.

I need to limit the removal to just any/all *trailing* CR and/or LF characters on the right-hand end of the string. Just like the RTrim function works with trailing spaces.

I'm thinking I may have to setup a loop, starting at the end of the length of the string.... [scurries off to the dev lab]

One way to do it is a loop, lopping off the last character as long as it's a match for CR or LF. Another method would be to use regex.

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