Counting consecutive repeated numbers greater than or less than.

Hi, new to the forum.
I dumped in some random numbers generated from a bitcoin dice site called primedice.
I'm trying to calculate the longest streaks of numbers less than 91 or above 9.
All of my numbers are in one column, what is the best formula to achieve this?

number dump:
number dump.xlsx

Hi, in my continued research I found this formula:
=MAX(FREQUENCY(IF(A1:A58728>9,ROW(A1:A58728)),IF(A1:A58728<=9,ROW(A1:A58728))))
=MAX(FREQUENCY(IF(A1:A58728<91,ROW(A1:A58728)),IF(A1:A58728>=91,ROW(A1:A58728))))
This gave me longest run of 84 for under 9, and 115 for over 91.
What am I doing wrong?

Thanks for your help. Can you tell me what these formulas are doing?
=MAX(FREQUENCY(IF(A1:A58728>9,ROW(A1:A58728)),IF(A1:A58728<=9,ROW(A1:A58728))))
=MAX(FREQUENCY(IF(A1:A58728<91,ROW(A1:A58728)),IF(A1:A58728>=91,ROW(A1:A58728))))

Hey Ron, I tried the formula with some adjustment to account for my scenario:

{=MAX(FREQUENCY(IF((L5:T5>=-1.5)*(L5:T5<=1.5),ROW(L5:T5)),IF((L5:T5>=-1.5)*(L5:T5<=1.5)=0,ROW(L5:T5))))}

I'm looking to have counted the consecutive occurrences of values >=-1.5 AND <=1.5 in L5:T5

The range is as follows:

0.4 -2.4 -1.6 -1.0 -1.3 -0.2 -0.1 -0.1 0.0

The array formula returns 7 whereas the consecutive occurrences are from -1.0 -1.3 -0.2 -0.1 -0.1 0.0 so expecting a result of 5