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Hi All,
I have First Name, Last Name and Email. I have to identify the type of email pattern which I had mentioned in Column D. Please find the attachment.
Hi All,
I have First Name, Last Name and Email. I have to identify the type of email pattern which I had mentioned in Column D. Please find the attachment.
Give this a shot:
=IFERROR(IF(ISERROR(FIND(LOWER(B2),C2,1)),$A$1&MID(C2,LEN(A2)+1,FIND("@",C2,1)-LEN(A2)-1),$A$1&MID(C2,LEN(A2)+1,FIND(LOWER(B2),C2,1)-LEN(A2)-1)&$B$1),"FirstInitialLastName")
Something like below. You could use RegEx, but since RegEx is system dependent... I used string manipulation.
Then in D2:
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=EmailPattern(A2,B2,C2)
Copy down.
Last edited by CK76; 11-08-2019 at 02:21 PM. Reason: Changed code a bit to reduce redundancy
?Progress isn't made by early risers. It's made by lazy men trying to find easier ways to do something.?
― Robert A. Heinlein
In some cases only lastname will be in email column.
Example
Greg Piggott [email protected]
The result should come like LastName
Try this then...
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Code is not working
Can't help you without you helping me. How is it not working?Code is not working
Small amendment to code as I noticed one thing. Check for x = lName rather than checking for length.
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Here is another macro that you can consider...
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Last edited by Rick Rothstein; 11-08-2019 at 07:28 PM.
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