Hi,
what is the 'real' formula of norm.s.dist(x,TRUE) ?
on the microsoft help page I can only find the formula for norm.s.dist(WRONG)
The given example there: =NORM.S.DIST(1.333333,TRUE) Example: 0.908788726 (description: Normal cumulative distribution function at 1.333333)
Could someone please let me know how I can calculate the 0,908.. on my own?
Thanks in advance,
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